早教吧作业答案频道 -->英语-->
一道高一英语语法题theboywasscoldedbecausehewascaught——applesfromtheneighbors‘stree.A、topickB、havingpickedC、pickD、picking
题目详情
一道高一英语语法题
the boy was scolded because he was caught ——apples from the neighbors‘s tree.
A、 to pick B、having picked C、pick D、picking
the boy was scolded because he was caught ——apples from the neighbors‘s tree.
A、 to pick B、having picked C、pick D、picking
▼优质解答
答案和解析
记住这个习惯用法
catch sb doing sth (bad / unpleasant) --------主动语态
be caught doing sth (bad / unpleasant) -------被动语态
catch sb doing sth (bad / unpleasant) --------主动语态
be caught doing sth (bad / unpleasant) -------被动语态
看了 一道高一英语语法题thebo...的网友还看了以下：
设a=(√5-1)/2,求(a^5+a^4-2a^3-a^2-a+2)/a^3-a∵2a=√5-1 2020-04-05 …
线性代数中为何|AA*|=||A|E|?设A为n阶矩阵(n³2),A*为A的伴随阵,证明.证明当R 2020-07-09 …
矩阵平方差设方阵A满足A²-A-2E=O,求A的逆矩阵.答案是1/2（A-E）.为啥不是1/2E, 2020-07-18 …
A,B均为三阶可逆矩阵,且A^3=0,则A：E-A,E+A均不可逆?B:E-A不可逆但E+A可逆? 2020-07-20 …
高数导数问题.设f(x)=(e^x-e^a)g(x)在x=a处可导,则函数g(x)应该满足条件是? 2020-07-20 …
已知向量a≠e,|e|=1,满足:任意t∈R.已知向量a不等于e,|e|=1,对任意t属于R,恒有 2020-07-25 …
一、已知数集M满足条件：若a∈M,则(1+a)/(1-a)∈M（a≠0,a≠±1）（1）若3∈M, 2020-07-30 …
已知向量a≠e,|e|=1,对任意t∈R,恒有|a-te|≥|a-e|,则（a,e皆为向量）A.a⊥ 2020-11-02 …
n阶方阵A满足A^2=O,E是n阶单位阵,则A.|E-A|≠0,但|E+A|=0B|E-An阶方阵A 2020-11-02 …
函数f[x]=logaXa大于0,且a不等于1,在2,3上最大值为1,则a=当a大于1时,f（x）图 2021-01-15 …