早教吧作业答案频道 -->英语-->
英语语法Idonothaveajob.IwouldfindonebutIDnotime.A.hadB.didn’thaveC.hadhadD.have为什么这里用have?
题目详情
英语语法
I do not have a job.I would find one but I __D_ no time.
A.had B.didn’t have C.had had D.have
为什么这里用have?
I do not have a job.I would find one but I __D_ no time.
A.had B.didn’t have C.had had D.have
为什么这里用have?
▼优质解答
答案和解析
后一句 是个并列句
前头的句子I would find one 是与现在相反的虚拟语气 省略了条件句,属于隐含的虚拟语气
but 并列的是与现在符合的真实句
原句=I would find one if i had time but I have no time.
前头的句子I would find one 是与现在相反的虚拟语气 省略了条件句,属于隐含的虚拟语气
but 并列的是与现在符合的真实句
原句=I would find one if i had time but I have no time.
看了英语语法Idonothavea...的网友还看了以下:
设a=(√5-1)/2,求(a^5+a^4-2a^3-a^2-a+2)/a^3-a∵2a=√5-1 2020-04-05 …
矩阵(E+A)^n等于什么?看到一个二阶的矩阵n次方=E^n+n(E)^(n-1)A,三阶的n次方 2020-06-12 …
设n(n≥2)阶矩阵A满足(E-A)(E+A)=O,其中E为n阶单位矩阵,若已知E+A的秩r(E+ 2020-06-12 …
高数导数问题.设f(x)=(e^x-e^a)g(x)在x=a处可导,则函数g(x)应该满足条件是? 2020-07-20 …
一、已知数集M满足条件:若a∈M,则(1+a)/(1-a)∈M(a≠0,a≠±1)(1)若3∈M, 2020-07-30 …
n阶方阵A满足A^2=O,E是n阶单位阵,则A.|E-A|≠0,但|E+A|=0B|E-An阶方阵A 2020-11-02 …
设数列{an}满足a(n+1)=2an+n^2-4n+1.(1)若a1=3,求证:存在f(n)=an 2020-11-19 …
一个求通项问题..a(n)=[a(n-1)]/[2a(n-1)+1]这个不是把分母乘过去,然后左右两 2020-12-14 …
函数f[x]=logaXa大于0,且a不等于1,在2,3上最大值为1,则a=当a大于1时,f(x)图 2021-01-15 …
试求矩阵B!设A,B为n阶矩阵,2A-B-AB=E,A^2=A,其中E为n阶单位矩阵.已知A=100 2021-02-05 …