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已知复数z1=15-5i(2+i)2,z2=a-3i(a∈R).(1)若a=2,求z1•.z2;(2)若z=z1z2是纯虚数,求a的值.

题目详情
已知复数z1=
15-5i
(2+i)2
z2=a-3i(a∈R).
(1)若a=2,求z1•
.
z2

(2)若z=
z1
z2
是纯虚数,求a的值.
▼优质解答
答案和解析
(1)z1=
15-5i
(2+i)2
=
15-5i
3+4i
=
(15-5i)(3-4i)
(3+4i)(3-4i)
=1-3i.
a=2时,∴z1•
.
z2
=(1-3i)(2+3i)=11-3i.
(2)z=
z1
z2
=
1-3i
a-3i
=
(1-3i)(a+3i)
(a-3i)(a+3i)
=
a+9+(3-3a)i
a2+9
是纯虚数,
a+9=0
3-3a≠0
,a=-9.