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求证sin²x-sin²y=sin(x+y)sin(x-y)

题目详情
求证sin²x-sin²y=sin(x+y)sin(x-y)
▼优质解答
答案和解析
答:
sin²x-sin²y
=(sinx+siny)(sinx-siny)
=2sin[(x+y)/2]cos[(x-y)/2] * 2cos[(x+y)/2]sin[(x-y)/2]
=sin(x+y)*sin(x-y)
所以:sin²x-sin²y=sin(x+y)*sin(x-y)