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计算(log43+log29)(log32-log92)
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计算(log43+log29)(log32-log92)
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答案和解析
(log43+log29)(log32-log92)
=(log(2)√3+log(2)9)(log32-log(3)√2)
=log(2)9√3*log(3)√2
=[(lg9√3)/lg2]*[(lg√2/lg3]
=5/2[(lg3)/lg2]*1/2[lg2/lg3]=5/4
=(log(2)√3+log(2)9)(log32-log(3)√2)
=log(2)9√3*log(3)√2
=[(lg9√3)/lg2]*[(lg√2/lg3]
=5/2[(lg3)/lg2]*1/2[lg2/lg3]=5/4
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