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计算:(1)(log32+log92)•(log43+log83);(2)lg5•lg8000+(lg23)2lg600-12lg0.036-12lg0.1.

题目详情
计算:
(1)(log32+log92)•(log43+log83);
(2)
lg5•lg8000+(lg2
3
)2
lg600-
1
2
lg0.036-
1
2
lg0.1
▼优质解答
答案和解析
(1)(log32+log92)•(log43+log83)=(
lg2
lg3
+
lg2
lg9
)(
lg3
lg4
+
lg3
lg8
)=
3lg2
2lg3
5lg3
6lg2
=
5
4

(2)
lg5•lg8000+(lg2
3
)2
lg600-
1
2
lg0.036-
1
2
lg0.1
=
lg5(3+3lg2)+3lg22
2+lg6-
1
2
(-3+2lg6)-
1
2
×(-1)
=
3
9
2
=
2
3