已知复数z满足z（-1+i）=2-i，则z=（）A.32-12iB.-32+12iC.32+12iD.-32-12i

Question

已知复数z满足 z（-1+i）=2-i，则z=（　　）

A.

(3)/(2)-(1)/(2)i

B. -

(3)/(2)+(1)/(2)i

C.

(3)/(2)+(1)/(2)i

D. -

(3)/(2)-(1)/(2)i

Answer 1

由 z（-1+i）=2-i，得z=(2-i)/(-1+i)=((2-i)(-1-i))/((-1+i)(-1-i))=(-3-i)/(2)=-(3)/(2)-(i)/(2)．
故选：D．