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求解几个正式的乘除与因式分解的算数题.①(x-1/2)^2(x^2+1/4)^2(x+1/2)^2②(-3x^2.y^3.z).①(x-1/2)^2(x^2+1/4)^2(x+1/2)^2②(-3x^2.y^3.z).x^3(x^2.y)^2÷9x^4.y^5
题目详情
求解几个正式的乘除与因式分解的算数题.①(x-1/2)^2(x^2+1/4)^2(x+1/2)^2 ②(-3x^2.y^3.z).
①(x-1/2)^2(x^2+1/4)^2(x+1/2)^2
②(-3x^2.y^3.z).x^3(x^2.y)^2÷9x^4.y^5
①(x-1/2)^2(x^2+1/4)^2(x+1/2)^2
②(-3x^2.y^3.z).x^3(x^2.y)^2÷9x^4.y^5
▼优质解答
答案和解析
①(x-1/2)^2(x^2+1/4)^2(x+1/2)^2
=(x-1/2)^2(x+1/2)^2(x^2+1/4)^2
=[(x-1/2)(x+1/2)]^2(x^2+1/4)^2
=(x²-1/4)^2(x^2+1/4)^2
=[(x²-1/4)(x^2+1/4)]^2
=(x⁴-1/16)²
=x^8-1/8x^4+1/256
②(-3x^2.y^3.z).x^3(x^2.y)^2÷9x^4.y^5
=﹣3x^5*y³*z*x^4y^2/9x^4 *y^5
=﹣3x^9*y^5*z/9x^4 *y^5
=﹣x^5y^10*z/3
=(x-1/2)^2(x+1/2)^2(x^2+1/4)^2
=[(x-1/2)(x+1/2)]^2(x^2+1/4)^2
=(x²-1/4)^2(x^2+1/4)^2
=[(x²-1/4)(x^2+1/4)]^2
=(x⁴-1/16)²
=x^8-1/8x^4+1/256
②(-3x^2.y^3.z).x^3(x^2.y)^2÷9x^4.y^5
=﹣3x^5*y³*z*x^4y^2/9x^4 *y^5
=﹣3x^9*y^5*z/9x^4 *y^5
=﹣x^5y^10*z/3
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