早教吧作业答案频道 -->其他-->
求英语大神翻译TheMinimumPaymentisthegreaterof:(i)2.1%ofthenewBalanceshownonamonthlystatement,plusthegreaterofanyamountbywhichthenewBalanceexceedsyourCreditLimitoranyamountpastduefromthepriormonth;or(
题目详情
求英语大神 翻译
The Minimum Payment is the greater of: (i) 2.1% of the new Balance shown on a monthly statement, plus the greater of any amount by which the new Balance exceeds your Credit Limit or any amount past due from the prior month; or (ii) $10. If the new Balance is less than $10, the Minimum Payment is the new Balance.
The Minimum Payment is the greater of: (i) 2.1% of the new Balance shown on a monthly statement, plus the greater of any amount by which the new Balance exceeds your Credit Limit or any amount past due from the prior month; or (ii) $10. If the new Balance is less than $10, the Minimum Payment is the new Balance.
▼优质解答
答案和解析
最低还款额是两者中大的数:(i)在月结单显示的新平衡的2.1%,加上由新的余额超过信用额度的部分和上月滞付的全部金额;或(ii)10美元。如果新的余额少于10元,最低还款额是新的平衡。
看了 求英语大神翻译TheMini...的网友还看了以下:
n次齐次函数设二元函数f(x,y),有:f(tx,ty)=t^n·f(x,y),求证:x·(f对x 2020-05-13 …
E(x)=f(x+1/2)-1在R上为奇函数,an=f(0)+f(1/n)+f(2/n)+…+f[ 2020-06-07 …
已知F(x)=f(x+1/2)-1是R上的奇函数,设an=f(0)+f(1/n)+f(2/n)+. 2020-06-07 …
T~t(n),证明T^2~F(1,n) 2020-06-12 …
数列题!f(x,y)对所有实数x,y都满足:f(0,y)=y+1,f(x+1,0)=f(x,1), 2020-06-12 …
设f(x)在(-∞,+∞)内可导,且F(x)=f(x^2-1)+f(1-x^2),证明F'(1)= 2020-06-15 …
函数f(x)对任意x∈R都有f(x)+f(1-x)=½(1)求f(½)和f(1/n)+f[(n-1 2020-06-30 …
斐波那契数列解法中的一个问题求解?这是解法裴波那契数列:1,1,2,3,5,8,13,.裴波那契数 2020-07-23 …
时间复杂度对数阶是什么样的T(n)=T(n-1)+1/n=T(n-2)+1/(n-1)+1/n=T 2020-07-30 …
若函数f(x)对任意x属于R,都有f(x)+f(1-x)=2(1)数列An=f(0)+f(1/n)+ 2020-10-31 …