（1）解分式方程：x−22x−1+1＝1.51−2x；（2）先化简，再求值：(1x+1+x2−2x+1x2−1)÷x−1x+1，其中x=2．

Question

（1）解分式方程：(x−2)/(2x−1)+1＝(1.5)/(1−2x)；
（2）先化简，再求值：((1)/(x+1)+(x2−2x+1)/(x2−1))÷(x−1)/(x+1)，其中x=2．(x−2)/(2x−1)+1＝(1.5)/(1−2x)；
（2）先化简，再求值：((1)/(x+1)+(x2−2x+1)/(x2−1))÷(x−1)/(x+1)，其中x=2．(x−2)/(2x−1)x−2x−22x−12x−1(1.5)/(1−2x)1.51.51−2x1−2x
((1)/(x+1)+(x2−2x+1)/(x2−1))÷(x−1)/(x+1)，其中x=2．(1)/(x+1)11x+1x+1(x2−2x+1)/(x2−1)x2−2x+1x2−2x+1x2−2x+1x2−2x+12−2x+1x2−1x2−1x2−1x2−12−1(x−1)/(x+1)x−1x−1x+1x+1

Answer 1

（1）方程变形得：x−22x−1+1=-1.52x−1，去分母得：x-2+2x-1=-1.5，解得：x=0.5，经检验x=0.5是增根，原分式方程无解；（2）原式=[1x+1+(x−1)2(x+1)(x−1)]•x+1x−1=x−1+(x−1)2(x+1)(x−1)•x+1x−1=x(x−1)(x...