早教吧作业答案频道 -->英语-->
Today,wewilldiscussanumberofsituates---beginnersofEnglishfailtodealwithproperly.AwhichBasCwhyDwhere我觉得应该选A,因为situations在句中并不做成分,所以不用where,
题目详情
Today,we will discuss a number of situates ---beginners of English fail to deal with properly.
A which B as C why D where
我觉得应该选A,因为situations在句中并不做成分,所以不用where,
A which B as C why D where
我觉得应该选A,因为situations在句中并不做成分,所以不用where,
▼优质解答
答案和解析
1. 答案:A.
2. 翻译:今天,我们将讨论许多英语初学者没能成功恰当地处理的情况.
3. 解释:
1)先行词是situations,它在定语从句中做deal with的宾语.
situations是物,所以只能用关系代词which代替它.
deal with中的with是介词,其后必须加上宾语,不能缺少.
2)即:which beginners of English fail to deal with properly
= beginners of English fail to deal with (which) properly
= beginners of English fail to deal with (the situations) properly.
2. 翻译:今天,我们将讨论许多英语初学者没能成功恰当地处理的情况.
3. 解释:
1)先行词是situations,它在定语从句中做deal with的宾语.
situations是物,所以只能用关系代词which代替它.
deal with中的with是介词,其后必须加上宾语,不能缺少.
2)即:which beginners of English fail to deal with properly
= beginners of English fail to deal with (which) properly
= beginners of English fail to deal with (the situations) properly.
看了 Today,wewilldi...的网友还看了以下:
Y=C+S+T怎么理解?我可以另外开贴,给50分Y=C+S+T怎么理解?我可以另外开贴,给50分支 2020-06-03 …
关于一元三次方程的根,高分请踊跃回答!我已经化简了;x1=1/6/a*z-2/y/a/z-1/3* 2020-07-09 …
求随机分布的概率已知:a、b、c为三个正常数x=random(0,4*a)''(x为0到4*a之间 2020-07-16 …
对任意x,y属于S,若x+y属于S,x-y属于S,则称S对加减封闭,S为R的真子集.证明:若S1, 2020-08-01 …
高一数学对任意x,y∈S,若x+y∈S,x-y∈S,则称S对加减封闭,S为R的真子集.(1)试举一 2020-08-01 …
对任意X,Y属于S,若X+Y属于S,X-Y属于S,则称S对加减封闭,S为R的真子集.①试举一例S② 2020-08-01 …
类比“两角和与差的正余弦公式”的形式,对于给定的两个函数,S(x)=ax−a−x2,C(x)=ax 2020-08-03 …
类比“两角和与差的正弦、余弦公式”的形式,对于给定的两个函数S(x)=[e^x-e^(-x)]/2 2020-08-03 …
类比两角和与差的正弦,余弦公式,对于给定的两个函数S(X)=(E^X-E^-X)/2,C(X)=( 2020-08-03 …
高一数学题(集合)对任意x,y∈S,若x+y∈S,x-y∈S,则称S对加减封闭,S为R的真子集证明: 2020-11-22 …