早教吧作业答案频道 -->数学-->
因式分解:(1)(-xy²)²*(x²y)三次方÷(x²y的五次)(2)3(x+1)²-5(x+1)(x-1)+2x(x-1)(3)8a三次-18a(4)2(a+b)²-a-b(5)(m/m-2-m/m+2)*2-m/m注明:这里的/
题目详情
因式分解:
(1)(-xy²)² * (x²y)三次方 ÷(x²y的五次) (2)3(x+1)²-5(x+1)(x-1)+2x(x-1)
(3)8a三次-18a (4)2(a+b)²-a-b
(5)(m/m-2 - m/m+2)* 2-m/m
注明:这里的/表示分数线,*表示乘号,如果可以每题至少2部,
(1)(-xy²)² * (x²y)三次方 ÷(x²y的五次) (2)3(x+1)²-5(x+1)(x-1)+2x(x-1)
(3)8a三次-18a (4)2(a+b)²-a-b
(5)(m/m-2 - m/m+2)* 2-m/m
注明:这里的/表示分数线,*表示乘号,如果可以每题至少2部,
▼优质解答
答案和解析
(1)(-xy²)² * (x²y)三次方 ÷(x²y的五次)
=x^2y^4*x^6y^3/(x^2y^5)
=x^6y^2
(2)3(x+1)²-5(x+1)(x-1)+2x(x-1)
=3(x+1)²-3(x+1)(x-1)-[2(x+1)(x-1)-2x(x-1)]
=3(x+1)[(x+1)-(x-1)]-2(x-1)[(x+1)-x]
=6(x+1)-2(x-1)
=4x+8
(3)8a三次-18a
=2a(4a²-9)
=2a(2a-3)(2a+3)
(4)2(a+b)²-a-b
=2(a+b)²-(a+b)
=(a+b)(2a+2b-1)
(5)[m/(m-2)- m/(m+2)]* (2-m)/m
=m/(m-2)* (2-m)/m- m/(m+2)* (2-m)/m
=-1-(2-m)/(m+2)
=-4/(m+2)
=x^2y^4*x^6y^3/(x^2y^5)
=x^6y^2
(2)3(x+1)²-5(x+1)(x-1)+2x(x-1)
=3(x+1)²-3(x+1)(x-1)-[2(x+1)(x-1)-2x(x-1)]
=3(x+1)[(x+1)-(x-1)]-2(x-1)[(x+1)-x]
=6(x+1)-2(x-1)
=4x+8
(3)8a三次-18a
=2a(4a²-9)
=2a(2a-3)(2a+3)
(4)2(a+b)²-a-b
=2(a+b)²-(a+b)
=(a+b)(2a+2b-1)
(5)[m/(m-2)- m/(m+2)]* (2-m)/m
=m/(m-2)* (2-m)/m- m/(m+2)* (2-m)/m
=-1-(2-m)/(m+2)
=-4/(m+2)
看了 因式分解:(1)(-xy²)...的网友还看了以下:
数学指数式化简(字母均为正数)要详细过程在线等急!谢谢1>>(5/6)a^(1/3)*b(-2)* 2020-04-27 …
设函数f(x)=(2^x)/(1+2^x)-1/2,[x]表示不超过x的最大整数,则函数y=[f( 2020-04-27 …
1+2+3+n=2分之1n(n+1),n是正整数,研究1*2+2*3+你(n+1),观察1*2=3 2020-05-20 …
4.2与1.2的差除它们的和,商是多少?正确的列式是[]A.(4.2-1.2)÷(4.2+1.2) 2020-06-27 …
求1+2+2^2+2^3+2^4+…+2^2014的值.设S=1+2+2^2+2^3+2^4+…+ 2020-07-09 …
当x∈[0,4]求定积分∫1/(1+√x)dx设√x=t则t∈[0,2]dx=2tdt原式=2∫t 2020-07-23 …
1.求:怎么证明2^x是增函数?2.怎么样证明2^x+(1/2)^x是在正实数范围内是增函数f(x 2020-08-01 …
1、若y^2-ay+1/4是完全平方公式,则a的值为.2、应用乘法公式计算:1.2345^2+2. 2020-08-01 …
已知道2[√X+√(Y-1)+√(Z-2)]=X+Y+Z,求X,Y,Z2[√X+√(Y-1)+√(Z 2020-11-01 …
(2000•内江)(1)观察下列等式:1(1+1×2)(1+2×2)=12(11+1×2−11+2× 2020-11-12 …