早教吧作业答案频道 -->数学-->
分解因式题.快1)9(2x-y)^2+12(2x-y)+42)x^2-4x(y+z)+4(y+z)^23)(x+5y)^2+(2x+10y)(3x-y)+(3x-y)^24)(1+x^2)^2-4x^25){x(a+b)+y(a+b)}÷(x+y)6)(m^2-49)÷(m+7)7)(-a^2b^2+16)÷(4-ab)8)2x^2-7x=09)x^2-12x+36=010)(2a-1)^2-(a+2)^2=011)2x^2-98=0
题目详情
分解因式题.快
1)9(2x-y)^2+12(2x-y)+4
2)x^2-4x(y+z)+4(y+z)^2
3)(x+5y)^2+(2x+10y)(3x-y)+(3x-y)^2
4)(1+x^2)^2-4x^2
5){x(a+b)+y(a+b)}÷(x+y)
6)(m^2-49)÷(m+7)
7)(-a^2b^2+16)÷(4-ab)
8)2x^2-7x=0
9) x^2-12x+36=0
10)(2a-1)^2-(a+2)^2=0
11)2x^2-98=0
1)9(2x-y)^2+12(2x-y)+4
2)x^2-4x(y+z)+4(y+z)^2
3)(x+5y)^2+(2x+10y)(3x-y)+(3x-y)^2
4)(1+x^2)^2-4x^2
5){x(a+b)+y(a+b)}÷(x+y)
6)(m^2-49)÷(m+7)
7)(-a^2b^2+16)÷(4-ab)
8)2x^2-7x=0
9) x^2-12x+36=0
10)(2a-1)^2-(a+2)^2=0
11)2x^2-98=0
▼优质解答
答案和解析
1)9(2x-y)^2+12(2x-y)+4
=(2x-y+4)^2
2)x^2-4x(y+z)+4(y+z)^2
=(x-y-z)^2
3)(x+5y)^2+(2x+10y)(3x-y)+(3x-y)^2
=(x+5y+3x-y)^2
=(4x+4y)^2
=16(x+y)^2
4)(1+x^2)^2-4x^2
=(1+x^2+2x)(1+x^2-2x)
=(1+x)^2(1-x)^2
5){x(a+b)+y(a+b)}÷(x+y)
=(a+b)(x+y)/(x+y)
=a+b
6)(m^2-49)÷(m+7)
=m-7
7)(-a^2b^2+16)÷(4-ab)
=4+ab
8)2x^2-7x=0
2x(x-3.5)=0
x1=0 x2=3.5
9) x^2-12x+36=0
(x-6)=0
x=6
10)(2a-1)^2-(a+2)^2=0
2a-1=a+2
a=3
11)2x^2-98=0
x=土7
=(2x-y+4)^2
2)x^2-4x(y+z)+4(y+z)^2
=(x-y-z)^2
3)(x+5y)^2+(2x+10y)(3x-y)+(3x-y)^2
=(x+5y+3x-y)^2
=(4x+4y)^2
=16(x+y)^2
4)(1+x^2)^2-4x^2
=(1+x^2+2x)(1+x^2-2x)
=(1+x)^2(1-x)^2
5){x(a+b)+y(a+b)}÷(x+y)
=(a+b)(x+y)/(x+y)
=a+b
6)(m^2-49)÷(m+7)
=m-7
7)(-a^2b^2+16)÷(4-ab)
=4+ab
8)2x^2-7x=0
2x(x-3.5)=0
x1=0 x2=3.5
9) x^2-12x+36=0
(x-6)=0
x=6
10)(2a-1)^2-(a+2)^2=0
2a-1=a+2
a=3
11)2x^2-98=0
x=土7
看了分解因式题.快1)9(2x-y...的网友还看了以下:
matlab中怎么求解多元非线性方程组,请高手给一个例子,和全部的求解命令,比如:u2=x^2*y 2020-05-16 …
方程x+y+z=12的非负整数解的个数[解析] 把x,y,z分别看作是x个1、y个1和z个1,则共 2020-05-16 …
曲面x3-2xy-xz2-y2z=11在点(3,1,-2)处的法线方程是()A.x+1821=y− 2020-06-11 …
曲面x2-2y2+z2-xyz-4x+2z=6在点(0,1,2)处的切平面方程为()A.3x+2( 2020-06-15 …
若x,y,z均为非负数,且满足x-1=y+12=z-23,则x2+y2+z2可取得的最小值为()( 2020-07-30 …
若(x-2z)2+|2x+13y|+|y+3|=0,则满足该等式的x、y、z的值分别是()A.x=1 2020-10-31 …
已知(2x-y-4)²+√(根号)x+3y+5=0,则x=y=2.已知有理数x、y、z满足x+y/3 2020-10-31 …
x+3y+7z=316{解得x+y+z=224x+4y+10z=362(1/x+1/z)×4+12/ 2020-10-31 …
三道初中数学题1,已知x/a+y/b+z/c=1,a/x+b/y+c/z=0,求证x^2/a^2+y 2020-11-01 …
一条初三关於比例的题目(附解法)(但我看不明)设10(y+z)=12(z+x)=15(x+y)试依y 2020-12-17 …