求高次和差公式推导,重金酬谢x^n-y^n=(x-y)[x^(n-1)+x^(n-2)y+x^(n-3)y^2+…+x^(n-k)y^(k-1)+y^(n-1)]x^(2n+1)+y^(2n+1)=(x+y)[x^(2n)-x^(2n-1)y+x^(2n-2)y^2+…+(-1)^kx^(2n-k)y^k+y^(2n)]求推倒

Question

求高次和差公式推导,重金酬谢 x^n-y^n=(x-y)[x^(n-1)+x^(n-2)y+x^(n-3)y^2+…+x^(n-k)y^(k-1)+y^(n-1)]
x^(2n+1)+y^(2n+1)=(x+y)[x^(2n)-x^(2n-1)y+x^(2n-2)y^2+…+
(-1)^k x^(2n-k) y^k+y^(2n)]
求推倒

Answer 1

你好：
这个证明得用数学归纳法了；