lg(x∧2-2x)/（9-x∧2）的导函数是什么不知这种复合函数算导数的步骤

Question

lg(x∧2-2x)/（9-x∧2）的导函数是什么
不知这种复合函数算导数的步骤

Answer 1

lg[(x²-2x)/(9-x²)]=(1/ln10)*ln[(x²-2x)/(9-x²)]
{lg[(x²-2x)/(9-x²)]}'=(1/ln10)*(9-x²)/(x²-x)*[(x²-2x)/(9-x²)]'
=(1/ln10)*(9-x²)/(x²-x)*[(2x-2)(9-x²)+(x²-2x)(2x)]/(9-x²)²
=(2/ln10)*/(x²-x)*[(x-1)(9-x²)+(x²-2x)x]/(9-x²)
=(2/ln10)*[1/x+(x²-2x)/(9-x²)(x-1)]