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tanx=-1,x属于[0,2π]x=
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tanx=-1,x属于[0,2π] x=
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答案和解析
x=2kπ-π/4
0<=x<=2π
x=π-π/4=3π/4
x=2π-π/4=7π/4
0<=x<=2π
x=π-π/4=3π/4
x=2π-π/4=7π/4
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