早教吧作业答案频道 -->数学-->
一道概述求极限的问题,谢谢回答(1)lim(sin2x-cos2x-1)/(cosx-sinx)(x趋向于四分之派)(2)lim(根号下(2x+1)-3)/(根号下(x-2)-根号2)x趋向4
题目详情
一道概述求极限的问题,谢谢回答
(1)lim(sin2x-cos2x-1)/(cosx-sinx)(x趋向于四分之派)
(2)lim(根号下(2x+1)-3)/(根号下(x-2)-根号2)
x趋向4
(1)lim(sin2x-cos2x-1)/(cosx-sinx)(x趋向于四分之派)
(2)lim(根号下(2x+1)-3)/(根号下(x-2)-根号2)
x趋向4
▼优质解答
答案和解析
(1)lim(sin2x-cos2x-1)/(cosx-sinx)
=lim{2sinxcosx-[2(cosx)^2-1]-1}/(cosx-sinx)
=lim2cosx(sinx-cosx)/(cosx-sinx)
=lim(-2)cosx (x趋向于π/4)
=-2^0.5
(2)x趋向于?
=lim{2sinxcosx-[2(cosx)^2-1]-1}/(cosx-sinx)
=lim2cosx(sinx-cosx)/(cosx-sinx)
=lim(-2)cosx (x趋向于π/4)
=-2^0.5
(2)x趋向于?
看了 一道概述求极限的问题,谢谢回...的网友还看了以下:
当lim(x-->0)(g(x))=0,证明lim(x-->0)(g(x)*sin1/x)=0li 2020-04-27 …
求极限:lim(1/x2-cot2x)x→0这么做错在哪:lim(sin2x-x2cos2x)/x 2020-05-16 …
求极限(x→0)lim((x^1/3)sin(1/x))我知道(x→0)lim((1/x)sinx 2020-07-08 …
lim(x趋于π/2)(tanx/tan3x)求极限过程是这样子的limtanx/tan3x=li 2020-07-21 …
lim趋近于无穷((x+c)/(x-c))^(x/2)=3,求clim(x→∞)[(x+c)/(x 2020-07-26 …
x→0时lim[1/ln(1+x^2)-1/(sinx)^2]=lim[(sinx)^2-ln(1 2020-08-02 …
x→0时lim[1/ln(1+x^2)-1/(sinx)^2]=lim[(sinx)^2-ln(1 2020-08-02 …
用洛必达法则求极限和用泰勒公式展开求极限的结果有没可能不同?lim[x->0](sinx-xcosx 2020-11-07 …
极限计算请问对于下面的极限的计算为何不正确1lim(x->0)[1/x^2-1/xtanx]因为li 2020-12-31 …
计算极限:lim(x->0)(sinx-x)/[x^2ln(1-x)]是否可以把分子拆开来做,再用无 2021-01-07 …