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1/(1^2)+1/(2^2)+1/(3^2)+1/(4^2)+1/(5^2)+1/(6^2)+1/(7^2)……1/(1^2)+1/(2^2)+1/(3^2)+1/(4^2)+1/(5^2)+1/(6^2)+1/(7^2)……+1/(n^2)=？
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1/(1^2)+1/(2^2)+1/(3^2)+1/(4^2)+1/(5^2)+1/(6^2)+1/(7^2)……
1/(1^2)+1/(2^2)+1/(3^2)+1/(4^2)+1/(5^2)+1/(6^2)+1/(7^2)……+1/(n^2)=？
1/(1^2)+1/(2^2)+1/(3^2)+1/(4^2)+1/(5^2)+1/(6^2)+1/(7^2)……+1/(n^2)=？
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悬赏这么高,翻书也要翻出来啊~
过程极其复杂,超出中学范畴,详见大学数学分析之傅里叶级数一章.
1/(1^2)+1/(3^2)+1/(5^2)+1/(7^2)……=π²/8.由此计算原式=π²/6.
过程极其复杂,超出中学范畴,详见大学数学分析之傅里叶级数一章.
1/(1^2)+1/(3^2)+1/(5^2)+1/(7^2)……=π²/8.由此计算原式=π²/6.
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