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(2008•高邮市)用简便方法计算(1)6.35-57+4.65-27=(2)813÷7+17×513=(3)34×0.25×43×4=

题目详情
(2008•高邮市)用简便方法计算
(1)6.35-
5
7
+4.65-
2
7
=
(2)
8
13
÷7+
1
7
×
5
13
=
(3)
3
4
×0.25×
4
3
×4=

5
7
+4.65-
2
7
=
(2)
8
13
÷7+
1
7
×
5
13
=
(3)
3
4
×0.25×
4
3
×4=
5
7
5577
2
7
=
(2)
8
13
÷7+
1
7
×
5
13
=
(3)
3
4
×0.25×
4
3
×4=
2
7
2277
8
13
÷7+
1
7
×
5
13
=
(3)
3
4
×0.25×
4
3
×4=
8
13
881313
1
7
×
5
13
=
(3)
3
4
×0.25×
4
3
×4=
1
7
1177
5
13
551313
3
4
×0.25×
4
3
×4=
3
4
3344
4
3
×4=
4
3
4433
▼优质解答
答案和解析
(1)6.35-
5
7
+4.65-
2
7

=6.35+4.65-(
5
7
+
2
7
),
=11-1,
=10;

(2)
8
13
÷7+
1
7
×
5
13
=
=
8
13
×
1
7
+
1
7
×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
5
7
555777+4.65-
2
7

=6.35+4.65-(
5
7
+
2
7
),
=11-1,
=10;

(2)
8
13
÷7+
1
7
×
5
13
=
=
8
13
×
1
7
+
1
7
×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
2
7
222777
=6.35+4.65-(
5
7
+
2
7
),
=11-1,
=10;

(2)
8
13
÷7+
1
7
×
5
13
=
=
8
13
×
1
7
+
1
7
×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
5
7
555777+
2
7
222777),
=11-1,
=10;

(2)
8
13
÷7+
1
7
×
5
13
=
=
8
13
×
1
7
+
1
7
×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
8
13
888131313÷7+
1
7
×
5
13
=
=
8
13
×
1
7
+
1
7
×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
1
7
111777×
5
13
555131313=
=
8
13
×
1
7
+
1
7
×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
8
13
888131313×
1
7
111777+
1
7
×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
1
7
111777×
5
13

=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
5
13
555131313,
=(
8
13
+
5
13
)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
8
13
888131313+
5
13
555131313)×
1
7

=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
1
7
111777,
=1×
1
7

=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
1
7
111777,
=
1
7


(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
1
7
111777;

(3)
3
4
×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
3
4
333444×0.25×
4
3
×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
4
3
444333×4
=(
3
4
×
4
3
)×(0.25×4),
=1×1,
=1.
3
4
333444×
4
3
444333)×(0.25×4),
=1×1,
=1.