早教吧作业答案频道 -->数学-->
(4k2+7k)+(-k2+3k-1)(5y+3x-15z2)-(12y+7x+z2).(3k2+7k)+(4k2-3k+1)(3x2+2xy-1/2x)-(2x2-xy+x)(1/2xy+y2+1)+(x2-1/2xy-2y2-1)(m2-3m+2)-(4m-2n-1)-5(x2-3)-2(3x2+5)有60分
题目详情
(4k2+7k)+(-k2+3k-1)
(5y+3x-15z2)-(12y+7x+z2).
(3k2+7k)+(4k2-3k+1)
(3x2+2xy-1/2x)-(2x2-xy+x)
(1/2xy+y2+1)+(x2-1/2xy-2y2-1)
(m2-3m+2)-(4m-2n-1)
-5(x2-3)-2(3x2+5)
有60分
(5y+3x-15z2)-(12y+7x+z2).
(3k2+7k)+(4k2-3k+1)
(3x2+2xy-1/2x)-(2x2-xy+x)
(1/2xy+y2+1)+(x2-1/2xy-2y2-1)
(m2-3m+2)-(4m-2n-1)
-5(x2-3)-2(3x2+5)
有60分
▼优质解答
答案和解析
(4k2+7k)+(-k2+3k-1)=3k²+10k-1
(5y+3x-15z2)-(12y+7x+z2)=-7y-4x-16z²
.
(3k2+7k)+(4k2-3k+1)=7k²+4k+1
(3x2+2xy-1/2x)-(2x2-xy+x)=x²+3xy-3x/2
(1/2xy+y2+1)+(x2-1/2xy-2y2-1)=x²-y²
(m2-3m+2)-(4m-2n-1)=m²-7m+2n+3
-5(x2-3)-2(3x2+5)=-11x²+5
希望对你有所帮助
(5y+3x-15z2)-(12y+7x+z2)=-7y-4x-16z²
.
(3k2+7k)+(4k2-3k+1)=7k²+4k+1
(3x2+2xy-1/2x)-(2x2-xy+x)=x²+3xy-3x/2
(1/2xy+y2+1)+(x2-1/2xy-2y2-1)=x²-y²
(m2-3m+2)-(4m-2n-1)=m²-7m+2n+3
-5(x2-3)-2(3x2+5)=-11x²+5
希望对你有所帮助
看了 (4k2+7k)+(-k2+...的网友还看了以下:
已知a大于b大于c,且a+b+c=0,方程ax^2+bx+c=0的两个根为x1,x2,若x1^2+ 2020-05-19 …
√(x1^2+1)-√(x2^2+1)-a(x1-x2)=(x1-x2)((x1+x2/(√x1^ 2020-07-03 …
如果对任意x1,x2∈R,都有f[(x1+x2)/2]≤1/2[f(x1)+f(x2),则称函数f 2020-07-29 …
数学分析齐次函数和欧拉定理的两个问题(不是很难,1、已知函数f(x1,x2)=(x1^2+x2^2 2020-08-02 …
设等比数列z1,z2,z3,…,zn,….其中z1=1,z2=a+bi,z3=b+ai(a,b∈R且 2020-10-31 …
(x1+x2)(x1-x2)/2+(y1-y2)(y1+y2)=0,是怎么到[(y1-y2)/(x1 2020-10-31 …
已知x,y,z为实数,若x2+y2=1,y2+z2=2,z2+x2=2.则xy=yz=xz的最小值是 2020-11-01 …
设A为5*4矩阵,若Ax=β有解,η1,η2是其两个特解,Ax=0的基础解系是X1,X2,则(A)A 2020-11-02 …
一个根式的化简√(x1^2+1)-√(x2^2+1)怎么化简成(x1^2-x2^2)/{√(x1^2 2020-11-07 …
1若x^2+1/x^2=2cosα(x∈R且x≠0),则复数2cosα+xi的模是?2抛物线y=-x 2021-02-03 …