［紧急求助］1/x^4+x^2+1的不定积分?

Question

［紧急求助］1/x^4+x^2+1的不定积分?

Answer 1

∫1/(x⁴+x²+1) dx= (1/2)∫(x+1)/(x²+x+1) dx - (1/2)∫(x-1)/(x²-x+1) dx= (1/2)[(1/2)∫(2x+1)/(x²+x+1) dx + (1/2)∫1/(x²+x+1) dx]- (1/2)[(1/2)∫(2x-1)/(x²-x+1) dx - (1...