求证：an=[√（4n-3）-1]/21/(a1+1)+1/(a1+1)(a2+1)+1/(a1+1)(a2+1)(a3+1)+.+1/(a1+1)(a2+1)(a3+1)...(an+1)＜3对于任意n包含于N+，都有an=[√（4n-3）-1]/2求证1/(a1+1)+1/(a1+1)(a2+1)+1/(a1+1)(a2+1)(a3+1)+......+1/(a1+1)(a2+1)(a3+1)...(an

题目详情

求证：an=[√（4n-3）-1]/2
1/(a1+1)+1/(a1+1)(a2+1)+1/(a1+1)(a2+1)(a3+1)+.+1/(a1+1)(a2+1)(a3+1)...(an+1)＜3
对于任意n包含于N+，都有an=[√（4n-3）-1]/2
求证1/(a1+1)+1/(a1+1)(a2+1)+1/(a1+1)(a2+1)(a3+1)+......+1/(a1+1)(a2+1)(a3+1)...(an+1)＜3

▼优质解答

答案和解析

1/（an+1）=2/((4n-3)^(1/2)+1)<2/(2+1)=2/3
下来直接代进去,成2/3等比数列的求和

看了求证：an=[√（4n-3）...的网友还看了以下：