(-2x^2y)^3+8(x^2)^2×(-x)^2(-y^3)^2-(y^4)^2·(-y)^5(a-b)^2(b-a)^4(b-a)^3(y-x)^2(x-y)+(x-y)^3+3(x-y)^2(y-x)

Question

(-2x^2y)^3+8(x^2)^2×(-x)^2(-y^3)^2
-(y^4)^2·(-y)^5
(a-b)^2(b-a)^4(b-a)^3
(y-x)^2(x-y)+(x-y)^3+3(x-y)^2(y-x)

Answer 1

(-2x^2y)^3+8(x^2)^2×(-x)^2(-y^3)^2
=-8x^6y^3+8x^4*x^2y^6
=-8x^6y^3+8x^4*x^2y^6
=8x^4y^3(y^3-x^3)
-(y^4)^2·(-y)^5
=-y^8*(-y^5)
=y^13
(a-b)^2(b-a)^4(b-a)^3
=-(a-b)^2(a-b)^4(a-b)^3
=-(a-b)^9
(y-x)^2(x-y)+(x-y)^3+3(x-y)^2(y-x)
=(x-y)^2(x-y)+(x-y)^3-3(x-y)^2(x-y)
=(x-y)^3+(x-y)^3-3(x-y)^3
=-(x-y)^3