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函数f(x)=sin(ωx+φ)(ω>0,|φ|<π2)的部分图象如图所示,如果x1,x2∈(-π6,π3),且f(x1)=f(x2),则f(x1+x2)=()A.12B.22C.1D.32
题目详情
函数f(x)=sin(ωx+φ)(ω>0,|φ|<
)的部分图象如图所示,如果x1,x2∈(-
,
),且f(x1)=f(x2),则f(x1+x2)=( )

π |
2 |
π |
6 |
π |
3 |

▼优质解答
答案和解析
由图知,T=2×(
+
)=π,
∴ω=2,因为函数的图象经过(-
),0=sin(-
+φ)
∵|φ|<
,所以φ=
,
∴f(x)=sin(2x+
),x1+x2=2×
=
,
所以f(x1+x2)=sin
=
.
故选:D.
π |
3 |
π |
6 |
∴ω=2,因为函数的图象经过(-
π |
6 |
π |
3 |
∵|φ|<
π |
2 |
π |
3 |
∴f(x)=sin(2x+
π |
3 |
π |
12 |
π |
6 |
所以f(x1+x2)=sin
2π |
3 |
| ||
2 |
故选:D.
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