Thankstothe------doctor,thegirlgaveupkillingherself.Thegirlshouldfacethedifficultybravely.Wealllearnby-------.A.experienced,experienceB.experiencing.experiencedC.experiencing.experienced为什么?

题目详情

Thanks to the ------doctor,the girl gave up killing herself .
The girl should face the difficulty bravely.We all learn by -------.
A.experienced ,experience
B.experiencing.experienced
C.experiencing.experienced 为什么?

▼优质解答

答案和解析

A.experienced adj.有经验的,经验丰富的
experience n.经验,阅历.
experience的形容词形式只有experienced ,没有experiencing

看了Thankstothe----...的网友还看了以下：

用定义证明函数f(x)=（1\e^x-1）+（1\2）是奇函数急吖借问下2楼的解法f(-x)=1/ 　2020-05-13 …

limx->0(e^x+e^2+e^3)/3lim(x~0)((e^x+e^2x+e^3x)/3) 　2020-05-17 …

设a>0,f(x)=e^x/a+a/e^x是R上的偶函数,求a值.∵f(x)=e^x/a+a/e^ 　2020-05-17 …

∫(0,+∞)xe^x/(1+e^x)^2dx,求出来了,但是感觉不对!原式=-∫xd[1/(1+ 　2020-06-12 …

∫(0,+∞)xe^x/(1+e^x)^2dx,求出来了,但是感觉不对!用定积分先求出了.最后正无　2020-06-12 …

协方差cov(X+20,Y+10)=cov(X,知道了COV(X+a,Y+b)=E[(X+a)(Y 　2020-06-17 …

已知函数y=(e^x-a)^2+(e^(-x)-a)^2(a属于R,a不等于0),求y的最小值Y= 　2020-07-21 …

D(X)=E[X-E(X)]^2=E{X^2-2XE(X)+[E(X)]^2}=E(X^2)-2[ 　2020-07-21 …

计算∫(上限+∞下限0)xe^(-x)/(1+e^(-x))^2其中过程是∫xe^(-x)dx/( 　2020-07-31 …

[ln(x+e^x)]/x=lim(x->0)(1+e^x)/(x+e^x)怎么得到的?原题limx 　2020-11-01 …