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计算题:(1)3.5×123+0.35×10+213×350%;(2)[249+(325-1115)×1111]+4.02;(3)(20-221×1)+(19-221×2)+(18-221×3)++(19-221×2)+(18-221×3)+…+(1-221×20)

题目详情
计算题:
(1)3.5×1
2
3
+0.35×10+2
1
3
×350%;
(2)[2
4
9
+(3
2
5
-
11
15
)×1
1
11
]+4.02;
(3)(20-
2
21
×1)+(19-
2
21
×2)+(18-
2
21
×3)++(19-
2
21
×2)+(18-
2
21
×3)+…+(1-
2
21
×20)
▼优质解答
答案和解析
(1)3.5×1
2
3
+0.35×10+2
1
3
×350%
=3.5×1
2
3
+3.5×1+2
1
3
×3.5
=3.5×(1
2
3
+1+2
1
3

=3.5×5
=17.5;
(2)[2
4
9
+(3
2
5
-
11
15
)×1
1
11
]+4.02
=[2
4
9
+2
2
3
×1
1
11
]+4.02
=[2
4
9
+2
10
11
]+4.02
=5
35
99
+4.02
=9
1849
4950

(3)(20-
2
21
×1)+(19-
2
21
×2)+(18-
2
21
×3)+…+(1-
2
21
×20)
=(20+19+18+…+1)-
2
21
×(1+2+3+…+20)
=(20+19+18+…+1)×(1-
2
21

=[(20+1)×20÷2]×
19
21

=210×
19
21

=190.