已知tanx=2,(1)求2/3sin^2x+1/4cos^2x的值(2)求2sin^2x-sinxcosx+cos^2x的值
(1) 2/3 sin^2 x + 1/4 os^2 x
=1/4+ 5/12 sin^2 x
=1/4 + 5/12(sin^2 x)(sin^2 x + cos^2 x)
=1/4 + 5/12 (tan^2 x)(tan^2 x +1)
=1/4+ 5/12 * 4/(4 +1) = 7/12
(2)2sin^2x-sin x cos x+cos^2x
= 1 + sin^2x-sin x cos x
= 1+ (sin^2x-sin x cos x)(sin^2 x + cos^2 x)
= 1+ (tan^2x-tan x)(tan^2 x +1)
= 1 + (4-2)(4+1)
= 7/5
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