无穷小代换,帮看看哪一步错了x→0lim[(sinx)sin(1-cos)^2]/(x^4+x^5)=sin(1-cos)^2/(x^3+x^4)=sin(x^4/4)/(x^3+x^4)=1/4

Question

无穷小代换,帮看看哪一步错了
x→0
lim[(sinx)sin(1-cos)^2]/(x^4+x^5)
=sin(1-cos)^2/(x^3+x^4)
=sin(x^4/4)/(x^3+x^4)=1/4

Answer 1

最后
=sin(x^4/4)/(x^3+x^4)
=(x^4/4)/(x^3+x^4)
=x/[4(1+x)]
所以=0