e^y*sinx-y+1=0求dy/dx其中x=0烦死了.e^y*sinx-y+1=0=>y(0)=1为什么要这一步！

Question

e^y*sinx-y+1=0 求dy/dx 其中x=0 烦死了.
e^y*sinx - y+1 = 0 => y(0) = 1
为什么要这一步！

Answer 1

e^y*sinx - y+1 = 0 => y(0) = 1
隐函数求导：
e^y * y' * sinx + e^y * cosx - y' = 0
=> y'(0) = e