早教吧作业答案频道 -->数学-->
把下列各式分解因式,(1)6(2p-q)²-11(q-2p)+3(2)a³-5a²b+6ab²(3)x³+9x²+26x+24(4)xˆ6-xˆ4-9x²+36(5)axˆ5-10axˆ4+16ax³
题目详情
把下列各式分解因式,
(1)6(2p-q)²-11(q-2p)+3 (2)a³-5a²b+6ab² (3)x³+9x²+26x+24 (4)xˆ6-xˆ4-9x²+36 (5)axˆ5-10axˆ4+16ax³
(1)6(2p-q)²-11(q-2p)+3 (2)a³-5a²b+6ab² (3)x³+9x²+26x+24 (4)xˆ6-xˆ4-9x²+36 (5)axˆ5-10axˆ4+16ax³
▼优质解答
答案和解析
(1)6(2p-q)²-11(q-2p)+3
=6(2p-q)²+11(2p-q)+3
=[3(2p-q)+1][2(2p-q)+3]
=(6p-3q+1)(4p-2q+3)
(2)a³-5a²b+6ab²=a(a²-5ab+6b²)=a(a-2b)(a-3b)
(3)x³+9x²+26x+24 =(x³+2x²)+(7x²+14x)+(12x+24)
=x²(x+2)+7x(x+2)+12(x+2)
=(x+2)(x²+7x+12)
=(x+2)(x+3)(x+4)
(4)xˆ6-xˆ4-9x²+36
(5)axˆ5-10axˆ4+16ax³=ax³(x²-10x+16)=ax³(x-2)(x-8)
=6(2p-q)²+11(2p-q)+3
=[3(2p-q)+1][2(2p-q)+3]
=(6p-3q+1)(4p-2q+3)
(2)a³-5a²b+6ab²=a(a²-5ab+6b²)=a(a-2b)(a-3b)
(3)x³+9x²+26x+24 =(x³+2x²)+(7x²+14x)+(12x+24)
=x²(x+2)+7x(x+2)+12(x+2)
=(x+2)(x²+7x+12)
=(x+2)(x+3)(x+4)
(4)xˆ6-xˆ4-9x²+36
(5)axˆ5-10axˆ4+16ax³=ax³(x²-10x+16)=ax³(x-2)(x-8)
看了 把下列各式分解因式,(1)6...的网友还看了以下：
值域：y=x^2-x/x^2-x+1要用分离常数法!y=(x^2-x)/(x^2-x+1)=(x^ 2020-04-09 …
解方程-1/X(X+1)+1/(X+1)(X+2)+.+1/(X+2009)(X+2010)+1/ 2020-05-16 …
x(x+1)/1+(x+1)(x+2)/1+（x+2)(x+3)/1+......+(x+2012 2020-06-03 …
∫(0,+∞)xe^x/(1+e^x)^2dx,求出来了,但是感觉不对!用定积分先求出了.最后正无 2020-06-12 …
1+x+x(x+1)+x(x+1)的平方=1+x+x(x+1)+x(x+1)2（为次方）=(1+x 2020-06-12 …
设X≥1,比较因为比较x3与x2-x+1的大小解x-（x-x+1）=x-x+x-1=x（x-1）+ 2020-06-18 …
1.7/x²-1+8/x²-2x=37-9x/x^3-x²-x+12.3/x²+x-2=x/x-1 2020-07-18 …
F(x)=x(e^x-1)-ax^2,若当x≥0时f(x)≥0,求a的取值范围?f(xF(x)=x 2020-07-26 …
请阅读下面的题目及其"解法"解方程x(x-1)/x-1=x+1/x-1解方程x（x-1）/x-1= 2020-07-31 …
五道分式方程1.10/(2x-1)+5/(1-2x)=22.1/(x-1)(x-2)=1/(x-4) 2021-01-24 …