早教吧作业答案频道 -->英语-->
一道GRE关于四分位的题目求详解ThecompanyawhichMarkisemployedhas80employees,eachofwomhasadifferentsalary.Mark'ssalaryof$43,700isthesecond-highestsalaryinthefirstquartileofthe80salaries.Iftheconmpanywereto
题目详情
一道GRE关于四分位的题目求详解
The company a which Mark is employed has 80 employees,each of wom has a different salary.Mark's salary of $ 43,700 is the second-highest salary in the first quartile of the 80 salaries.If the conmpany were to hire 8 new employees at salaries that are less than the lowest of the 80 salaries,what would Mark's salary be with respect to the quartiles of the 88 salaries at the company,assuming no other changes in the salaries?
The fifth-lowest salary in the second quartile.
The company a which Mark is employed has 80 employees,each of wom has a different salary.Mark's salary of $ 43,700 is the second-highest salary in the first quartile of the 80 salaries.If the conmpany were to hire 8 new employees at salaries that are less than the lowest of the 80 salaries,what would Mark's salary be with respect to the quartiles of the 88 salaries at the company,assuming no other changes in the salaries?
The fifth-lowest salary in the second quartile.
▼优质解答
答案和解析
公司80人,分四组(20人1组)
分别是 first(第61-80位),second(41-60),third(21-40),fourth(1-20)quartile
Mark 薪金原是在公司是1组第2位高,即first quartile 中的第62位
增加8人後,分四组(22人1组)
四组变化分别是 (67-88),(45-66),(23-44),(1-22)
因此第62位的Mark现在变成second quartile,(66 65 64 63 62..)的倒数第5位(fifth-lowest)
分别是 first(第61-80位),second(41-60),third(21-40),fourth(1-20)quartile
Mark 薪金原是在公司是1组第2位高,即first quartile 中的第62位
增加8人後,分四组(22人1组)
四组变化分别是 (67-88),(45-66),(23-44),(1-22)
因此第62位的Mark现在变成second quartile,(66 65 64 63 62..)的倒数第5位(fifth-lowest)
看了 一道GRE关于四分位的题目求...的网友还看了以下:
已知a+b+c=H a+b+e=J a+d+e=K b+c+d=M c+d+e=N 求a=?b=? 2020-05-16 …
RSA算法中的mod计算问题RSA密文算法公式c=m^e%n例如有这样一道题,设m=15,e=3d 2020-05-16 …
设M是椭园:((x^2)/12)+((y^2)/4)=1上的一点,P,Q,T分别为M关于y轴,原点 2020-06-21 …
设E是直线上衣有界集合,m*E大于0,则对于任意小于m*E的正数c.恒有E的子集E1,使得m*E1 2020-06-23 …
重组字母为单词e,e,r,w,he,e,r,t,he,e,se,a,sw,m,s,ir,t,p,i 2020-07-09 …
一道很难的圆锥曲线题如图,已知椭圆E:x^2/100+y^2/25=1的上顶点为A,直线y=-4交 2020-07-17 …
设定圆(x+根号3)^2+y^2=16,动圆N过点F(根号3,0)且与圆M相切,记圆心N的轨迹为E 2020-07-26 …
1道初二几何题,Rt三角形ABC中,∠C=90度,M为AC中点,N为CB中点,E为AB中点,证明以C 2020-11-01 …
14gX在一定量的Y中恰好完全反应,生成44gM和18gN,变化的部分微观示意如图所示,有关说法正确 2020-11-07 …
已知点M(-1,0),N(1,0),曲线E上任意一点到M的距离均是到点N距离的3倍.(1)求曲线E的 2020-11-27 …