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Gmat数学,求简便算法~~Foreveryintegerkfrom1to10,inclusive,thekthtermofacertainsequenceisgivenby.IfTisthesumofthefirst10termsinthesequence,thenTis(A)greaterthan2(B)between1and2(C)between1/2and1(D)
题目详情
Gmat数学,求简便算法~~
For every integer k from 1 to 10, inclusive, the kth term of a certain sequence is given by . If T is the sum of the first 10 terms in the sequence, then T is
(A) greater than 2
(B) between 1 and 2
(C) between 1/2 and 1
(D) between 1/4 and 1/2
(E) between 1/4
the kth term of a certain sequence is given by (-1)^(k+1)乘以(1/2^k)
For every integer k from 1 to 10, inclusive, the kth term of a certain sequence is given by . If T is the sum of the first 10 terms in the sequence, then T is
(A) greater than 2
(B) between 1 and 2
(C) between 1/2 and 1
(D) between 1/4 and 1/2
(E) between 1/4
the kth term of a certain sequence is given by (-1)^(k+1)乘以(1/2^k)
▼优质解答
答案和解析
答案选D,解法如下:
the kth term of a certain sequence is given by (-1)^(k+1)乘以(1/2^k)
说明通项公式为:an=(-1)·(-1/2)^k
又因为K=10,已经是一个较大的数了,1-q^n,在n较大的情况下,是可以忽略的,因此
sn=a1/(1-q),代入即为:1/2除以1-(-1/2),答案为1/3.
the kth term of a certain sequence is given by (-1)^(k+1)乘以(1/2^k)
说明通项公式为:an=(-1)·(-1/2)^k
又因为K=10,已经是一个较大的数了,1-q^n,在n较大的情况下,是可以忽略的,因此
sn=a1/(1-q),代入即为:1/2除以1-(-1/2),答案为1/3.
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