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已知:(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ•mol-1(2)2Al(s)+32O2(g)=Al2O3(s)△H=-1675kJ•mol-1则2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为()A.-2491kJ•mol-1B.+859kJ•mol-1C.-1403
题目详情
已知:
(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ•mol-1
(2)2Al(s)+
O2(g)=Al2O3(s)△H=-1675kJ•mol-1
则 2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为( )
A.-2491 kJ•mol-1
B.+859 kJ•mol-1
C.-1403 kJ•mol-1
D.-859 kJ•mol-1
2-1
O2(g)=Al2O3(s)△H=-1675kJ•mol-1
则 2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为( )
A.-2491 kJ•mol-1
B.+859 kJ•mol-1
C.-1403 kJ•mol-1
D.-859 kJ•mol-1
3 3 2 2 223-1
23
-1
-1
-1
-1
(1)2Fe(s)+O2(g)=2FeO(s)△H=-544kJ•mol-1
(2)2Al(s)+
3 |
2 |
则 2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为( )
A.-2491 kJ•mol-1
B.+859 kJ•mol-1
C.-1403 kJ•mol-1
D.-859 kJ•mol-1
2-1
3 |
2 |
则 2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)的△H为( )
A.-2491 kJ•mol-1
B.+859 kJ•mol-1
C.-1403 kJ•mol-1
D.-859 kJ•mol-1
3 |
2 |
23
-1
-1
-1
-1
▼优质解答
答案和解析
已知:(1)2Fe(s)+O22(g)=2FeO(s)△H=-544kJ•mol-1-1
(2)2Al(s)+
O2(g)=Al2O3(s)△H=-1675kJ•mol-1
据盖斯定律,(2)-(1)×
得:2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)△H=-859KJ/mol
故选:D
3 3 32 2 2O22(g)=Al22O33(s)△H=-1675kJ•mol-1-1
据盖斯定律,(2)-(1)×
得:2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)△H=-859KJ/mol
故选:D
3 3 32 2 2得:2Al(s)+3FeO(s)=Al22O33(s)+3Fe(s)△H=-859KJ/mol
故选:D
(2)2Al(s)+
3 |
2 |
据盖斯定律,(2)-(1)×
3 |
2 |
故选:D
3 |
2 |
据盖斯定律,(2)-(1)×
3 |
2 |
故选:D
3 |
2 |
故选:D
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