求函数y=log(x-1)(x²-x)的定义域

Question

求函数y=log(x-1)(x²-x)的定义域

Answer 1

解由y=log(x-1)(x²-x)
知x-1＞0且x-1≠0且x^2-x＞0
即x＞1且x≠1且(x)(x-1)＞0
即x＞1且x≠2且x＞1或x＜0
即x＞1且x≠2
故函数的定义域为{x/x＞1且x≠2}