复数i6+1+i1−i在复平面上对应的点在第象限．

Question

复数i6+(1+i)/(1−i)在复平面上对应的点在第______象限．

Answer 1

∵i6+(1+i)/(1−i)
=i2+((1+i)2)/((1−i)(1+i))
=-1+(2i)/(2)
=-1+i．
∴复数i6+(1+i)/(1−i)在复平面上对应的点（-1，1）在第2象限．
故答案为：二．