解方程组[4x^2/(1+4x^2)]=y[4y^2/(1+4y^2)]=z[4z^2/(1+4z^2)]=x(xyz≠0)要有过程!

Question

解方程组
[4x^2/(1+4x^2)]=y
[4y^2/(1+4y^2)]=z
[4z^2/(1+4z^2)]=x
(xyz≠0)
要有过程!

Answer 1

由题目可知此三元方程组是轮换式,故x=y=z是原方程的解.
代入解得x=y=z=1/2