召唤组合数学达人!有奇数个变量,ei,i=1,2,.,2k+1满足：e1+e2=e2+e3+e(2k+1)=e3+e4=.e(2k-1)+e(2k)=e(2k)+e1+e(2k+1)=e(i)赋值{-k,.,-2,-1,0,1,2,.,k}值域{-k,.,-2,-1,0,1,2,.,k}只要举出一组满足条件的答案即可.

Question

召唤组合数学达人!
有奇数个变量,ei,i=1,2,.,2k+1
满足：e1+e2=
e2+e3+e(2k+1)=
e3+e4=
.
e(2k-1)+e(2k)=
e(2k)+e1+e(2k+1)=
e(i)赋值{-k,.,-2,-1,0,1,2,.,k}
值域{-k,.,-2,-1,0,1,2,.,k}
只要举出一组满足条件的答案即可.

Answer 1

我不是组合数学达人,我是平面几何达人.
满足的条件麻烦你好好写,让我能看懂!
m＝e1＋e2＝e3+e4＝……＝e(2k-1)+e(2k)我懂
m=e2+e3+e(2k+1)= e(2k)+e1+e(2k+1)是什么?
20分顶多招个平面几何达人,组合达人／数论达人得200分啊