早教吧作业答案频道 -->其他-->
脱式计算,能简算的要简算(70+0.wu)÷71.6+8.w×1.8÷0.18w6.9×3.7+w6.9×8.3+w6.936×10.10.u8×3u×1.u881.6÷[(3.w-1.u8)×0.8].
题目详情
脱式计算,能简算的要简算
| (70+0.wu)÷7 | 1.6+8.w×1.8÷0.18 |
| w6.9×3.7+w6.9×8.3+w6.9 | 36×10.1 |
| 0.u8×3u×1.u8 | 81.6÷[(3.w-1.u8)×0.8]. |
▼优质解答
答案和解析
①(70+0.52)÷7
=70.52÷7
=10.0z
②1.z+八.5×1.5÷0.1八
=1.z+12.z÷0.1八
=1.z+70
=71.z
③5z.5×3.7+5z.5×5.3+5z.5
=5z.5×(3.7+5.3+1)
=5z.5×10
=5z5
④3z×10.1
=3z×(10+0.1)
=3z×10+3z×0.1
=3z0+3.z
=3z3.z
⑤0.25×32×1.25
=0.25×5×八×1.25
=(0.25×5)×(八×1.25)
=1×10
=10
⑥51.z÷[(3.5-1.25)×0.八]
=51.z÷[3.5×0.八-1.25×0.八]
=51.z÷[2.72-1]
=51.z÷1.72
=30
=70.52÷7
=10.0z
②1.z+八.5×1.5÷0.1八
=1.z+12.z÷0.1八
=1.z+70
=71.z
③5z.5×3.7+5z.5×5.3+5z.5
=5z.5×(3.7+5.3+1)
=5z.5×10
=5z5
④3z×10.1
=3z×(10+0.1)
=3z×10+3z×0.1
=3z0+3.z
=3z3.z
⑤0.25×32×1.25
=0.25×5×八×1.25
=(0.25×5)×(八×1.25)
=1×10
=10
⑥51.z÷[(3.5-1.25)×0.八]
=51.z÷[3.5×0.八-1.25×0.八]
=51.z÷[2.72-1]
=51.z÷1.72
=30
看了脱式计算,能简算的要简算(70...的网友还看了以下:
对于正整数a,b,c(a小于等于b小于等于c)和非零实数x,y,z,w,若a的x次方=b的y次方= 2020-04-06 …
设w是1的n次根,w不等于1,求证w满足的方程1+z+z^2+z^3+...+z^n-1=0.w是 2020-06-22 …
下列各项,注音有误的一项是()A.蜿wān蜿蜒yán委wēi虚与委蛇yí逶wēi山岭逶迤B.伪wě 2020-07-13 …
(1)已知z为虚数,z+9z-2为实数,若z-2为纯虚数,求虚数z;(2)已知w=z+i(z∈C) 2020-07-30 …
(1)已知z为虚数,z+9z−2为实数,若z-2为纯虚数,求虚数z;(2)已知w=z+i(z∈C) 2020-07-30 …
有关复数的题目一.巳知1+x+x^2=0,求证:x^1979+x^1989+x^1999=0二.设 2020-08-01 …
有八个数w它,2十,0.•w•1,1十2w,0.w.1,2227是其的的n个,如果从小到八顺序排列时 2020-10-31 …
初一数学(一元一次方程)1.x/3-x/6=12.3x/2+4=x/5+x+13.0.4x-0.5= 2020-10-31 …
(1)下明的体重大约为w千克.(2)2010年5月1日上海世博会开幕式入园参观人数为21人.(3)光 2020-11-11 …
已知w为w^5=1的非零实根,则w(w+1)(w^2+1)=?不好意思,不是实根,我打错了.3楼,为 2020-12-07 …