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已知4x=3y,求代数式(x-2y)2-(x-y)(x+y)-2y2的值.
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已知4x=3y,求代数式(x-2y)2-(x-y)(x+y)-2y2的值.
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答案和解析
(x-2y)2-(x-y)(x+y)-2y2
=x2-4xy+4y2-(x2-y2)-2y2
=-4xy+3y2
=-y(4x-3y).
∵4x=3y,
∴原式=0.
=x2-4xy+4y2-(x2-y2)-2y2
=-4xy+3y2
=-y(4x-3y).
∵4x=3y,
∴原式=0.
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