谁能帮我做几道计算题计算：①（3-2i)+(-3+4i)②（3+4i)+(5-3i)-(4+4i)③(3+2i)(4-3i)④(4+2i)(5-6i)⑤1+i分之1-i⑥4-3i分之3+2i

Question

谁能帮我做几道计算题
计算：①（3-2i)+(-3+4i) ②（3+4i)+(5-3i)-(4+4i) ③(3+2i)(4-3i) ④(4+2i)(5-6i)
⑤1+i分之1-i ⑥4-3i分之3+2i

Answer 1

①（3-2i)+(-3+4i)=(3-3)+(-2+4)i=2i
②（3+4i)+(5-3i)-(4+4i)
=(3+5-4)+(4-3-4)i
=4-3i
③(3+2i)(4-3i)=12-9i+8i+6=18-i
④(4+2i)(5-6i)=20-24i+10i+12=32-14i
1-i/1+i=(1-i)²/(1+i)(1-i)=(1-2i+i²)/2=-i