二十个二次根式加解题过程

Question

二十个二次根式加解题过程

Answer 1

5√8-2√32+√50
=5*2√2-2*4√2+5√2
=√2(10-8+5)
=7√2
√6-√3/2-√2/3
=√6-√6/2-√6/3
=√6/6
(√45+√27)-(√4/3+√125)
=(3√5+3√3)-(2√3/3+5√5)
=-2√5+7√5/3
(√4a-√50b)-2(√b/2+√9a)
=(2√a-5√2b)-2(√2b/2+3√a)
=-4√a-6√2b
√4x*(√3x/2-√x/6)
=2√x(√6x/2-√6x/6)
=2√x*(√6x/3)
=2/3*|x|*√6
(x√y-y√x)÷√xy
=x√y÷√xy-y√x÷√xy
=√x-√y
(3√7+2√3)(2√3-3√7)
=(2√3)^2-(3√7)^2
=12-63
=-51
(√32-3√3)(4√2+√27)
=(4√2-3√3)(4√2+3√3)
=(4√2)^2-(3√3)^2
=32-27
=5
（1+√2-√3）（1-√2+√3）
=[1+(√2-√3)][1-(√2-√3)]
=1-(√2-√3)^2
=1-(2+3+2√6)
=-4-2√6
5√12×√18
=5*2√3*3√2
=30√6;
6√45×（-4√48）
=6*3√5*4*4√3
=288√15;
√(12a)×√(3a) /4
=√(36a^2)/4
=6a/4
=3a/2.