早教吧作业答案频道 -->英语-->
用英文答,证明题Forarandomvariablewithabinomialdistribution,B(n,p),ShowthatE(X)=npVar(X)=np(1-p)=npq,whereq=1-p.
题目详情
用英文答,证明题
For a random variable with a binomial distribution,B(n,p) ,Show that E(X)=np Var(X)=np(1-p)=npq ,where q=1-p.
For a random variable with a binomial distribution,B(n,p) ,Show that E(X)=np Var(X)=np(1-p)=npq ,where q=1-p.
▼优质解答
答案和解析
Answer. The probability that X=k is C_n^k p^k q^{n-k}, so we get
EX= \sum_0^n k C_n^k p^k q^{n-k} = p(\sum_0^n C_n^k p^k q^{n-k})_p
= p ((p+q)^n)_p
= p n(p+q)^{n-1}
= np
Here _p means taking partial derivative with respect to the variable p.
Similarly, you can work out \sum_0^n k(k+1) C_n^k p^k q^{n-k}, and deduce the value of \sum_0^n k^2 C_n^k p^k q^{n-k}, then Var X can be computed out.
But I compute out Var X = n^2 pq, rather npq. This should be checked.
EX= \sum_0^n k C_n^k p^k q^{n-k} = p(\sum_0^n C_n^k p^k q^{n-k})_p
= p ((p+q)^n)_p
= p n(p+q)^{n-1}
= np
Here _p means taking partial derivative with respect to the variable p.
Similarly, you can work out \sum_0^n k(k+1) C_n^k p^k q^{n-k}, and deduce the value of \sum_0^n k^2 C_n^k p^k q^{n-k}, then Var X can be computed out.
But I compute out Var X = n^2 pq, rather npq. This should be checked.
看了 用英文答,证明题Forara...的网友还看了以下:
receive这个单词地拼法,我不太肯定想请问一下.是以下哪一种拼法正确呢?(1)/R//E//C 2020-05-17 …
社会总资本扩大再生产的前提条件是( )A.I (v+m)=IIcB.II (v+m)=IcC.I ( 2020-06-05 …
ε1,ε2,...εn是n维欧式空间V的一组基,证明(1)α∈V使得(α,εi)=0(i=1,2. 2020-06-12 …
问即付年金终值S=A{(1+i)^n+1-1/i-1}s=终值a=年金i=利率n=期数公式对么是怎 2020-06-16 …
已知Sn={A|A=(a1,a2,a3,...,an),ai=0或1,i=1,2,...,n}(n 2020-07-19 …
ode45求多元微分方程functiondw=I(t,w)m=w(1)n=w(2)h=w(3)V= 2020-07-23 …
若V={(a+bi,c+di)|a,b,c,d∈R}其中i=√-1.则V对于通常的加法和数乘,在若 2020-07-26 …
用英文答,证明题Forarandomvariablewithabinomialdistributi 2020-08-01 …
关于利率贴现率问题求解,(1-V^5)/i=4怎么求?各位金融数学的大侠教教套用1/(1+i)=v 2020-08-02 …
组合英语单词:1.r,i,v,r,d,e2.t,i,w,e,h3.a,v,e,s,4.c,t,k,e 2020-11-29 …