早教吧作业答案频道 -->英语-->
英语翻译ForthePEFRdatas=38.8.Thestandarderrorofdisthus9.4,Forthe95%confidenceintervalwehave16degreesoffreedomandt=2.12.Hencethe95%confidenceintervalforthebiasis-2.1-(2.12´9.4)to-2.1+(2.12´
题目详情
英语翻译
For the PEFR data s = 38.8.The standard error of d is thus 9.4,For the 95% confidence interval we have 16 degrees of freedom and t = 2.12.Hence the 95% confidence interval for the bias is - 2.1- (2.12 ´ 9.4) to - 2.1+ (2.12 ´ 9.4) ,giving - 22.0 to 17.8 l/min.The standard error of the limit d - 2s is 16.3 l/min.The 95% confidence interval for the lower limit of agreement is - 79.7 - (2.12 ´16.3) to - 79.7 + (2.12 ´16.3) ,giving -114.3 to
- 45.1 l/min.For the upper limit of agreement the 95% confidence interval is 40.9 to 110.1l/min.These intervals are wide,reflecting the small sample size and the great variation of the
differences.They show,however,that even on the most optimistic interpretation there can be considerable discrepancies between the two meters and that the degree of agreement is not acceptable.
谢绝机译!
agreement不是协议的意思,qindajia,你再帮我想一想啊!
For the PEFR data s = 38.8.The standard error of d is thus 9.4,For the 95% confidence interval we have 16 degrees of freedom and t = 2.12.Hence the 95% confidence interval for the bias is - 2.1- (2.12 ´ 9.4) to - 2.1+ (2.12 ´ 9.4) ,giving - 22.0 to 17.8 l/min.The standard error of the limit d - 2s is 16.3 l/min.The 95% confidence interval for the lower limit of agreement is - 79.7 - (2.12 ´16.3) to - 79.7 + (2.12 ´16.3) ,giving -114.3 to
- 45.1 l/min.For the upper limit of agreement the 95% confidence interval is 40.9 to 110.1l/min.These intervals are wide,reflecting the small sample size and the great variation of the
differences.They show,however,that even on the most optimistic interpretation there can be considerable discrepancies between the two meters and that the degree of agreement is not acceptable.
谢绝机译!
agreement不是协议的意思,qindajia,你再帮我想一想啊!
▼优质解答
答案和解析
这好像是我答复的第三帖了.谢谢楼主的赏识.
For the PEFR data s = 38.8.The standard error of d is thus 9.4,对于PEFR(呼气流速变化率)数据s=38.8来说,那d的标准误差因此为9.4.For the 95% confidence interval we have 16 degrees of freedom and t = 2.12.对于95%的置信区间来说,我们有16的自由度,而t=2.12.Hence the 95% confidence interval for the bias is - 2.1- (2.12 ´ 9.4) to - 2.1+ (2.12 ´ 9.4) ,giving - 22.0 to 17.8 l/min.因此,对于偏差95%的置信区间为 - 2.1- (2.12 ´ 9.4) to - 2.1+ (2.12 ´ 9.4),给出为- 22.0 to 17.8 l/min.The standard error of the limit d - 2s is 16.3 l/min.极限d-2s的标准误差为16.3 l/min.The 95% confidence interval for the lower limit of agreement is - 79.7 - (2.12 ´16.3) to - 79.7 + (2.12 ´16.3) ,giving -114.3 to
- 45.1 l/min.对于协议下限的95%的置信区间为 - 79.7 - (2.12 ´16.3) to - 79.7 + (2.12 ´16.3),给出为 -114.3 to
- 45.1 l/min.For the upper limit of agreement the 95% confidence interval is 40.9 to 110.1l/min.对于协议的上限,95%的置信区间为40.9 to 110.1l/min.These intervals are wide,reflecting the small sample size and the great variation of the differences.这些区间比较宽,反映了较小的样本量和差别的巨大变化.They show,however,that even on the most optimistic interpretation there can be considerable discrepancies between the two meters and that the degree of agreement is not acceptable.可是它们表明了,即使是在最乐观的解释下,两台仪表之间都可能存在相当大的 差异,而且符合程度不能让人接受
For the PEFR data s = 38.8.The standard error of d is thus 9.4,对于PEFR(呼气流速变化率)数据s=38.8来说,那d的标准误差因此为9.4.For the 95% confidence interval we have 16 degrees of freedom and t = 2.12.对于95%的置信区间来说,我们有16的自由度,而t=2.12.Hence the 95% confidence interval for the bias is - 2.1- (2.12 ´ 9.4) to - 2.1+ (2.12 ´ 9.4) ,giving - 22.0 to 17.8 l/min.因此,对于偏差95%的置信区间为 - 2.1- (2.12 ´ 9.4) to - 2.1+ (2.12 ´ 9.4),给出为- 22.0 to 17.8 l/min.The standard error of the limit d - 2s is 16.3 l/min.极限d-2s的标准误差为16.3 l/min.The 95% confidence interval for the lower limit of agreement is - 79.7 - (2.12 ´16.3) to - 79.7 + (2.12 ´16.3) ,giving -114.3 to
- 45.1 l/min.对于协议下限的95%的置信区间为 - 79.7 - (2.12 ´16.3) to - 79.7 + (2.12 ´16.3),给出为 -114.3 to
- 45.1 l/min.For the upper limit of agreement the 95% confidence interval is 40.9 to 110.1l/min.对于协议的上限,95%的置信区间为40.9 to 110.1l/min.These intervals are wide,reflecting the small sample size and the great variation of the differences.这些区间比较宽,反映了较小的样本量和差别的巨大变化.They show,however,that even on the most optimistic interpretation there can be considerable discrepancies between the two meters and that the degree of agreement is not acceptable.可是它们表明了,即使是在最乐观的解释下,两台仪表之间都可能存在相当大的 差异,而且符合程度不能让人接受
看了 英语翻译ForthePEFR...的网友还看了以下:
根据3^2-1^2=8*1、5^3-3^2=8*2、7^2-5^2=8*3这个规律可得的结论是什么 2020-05-13 …
求1+2+2^2+2^3+2^4+…+2^2014的值.设S=1+2+2^2+2^3+2^4+…+ 2020-07-09 …
(1)-22-(-1)3(2)4-5*(-1/2)3(3)(-10)2/5×(-2/5)(4)(- 2020-07-22 …
xyz=1,x+y+z=2,x^2+y^2+z^2=3,求x,y,z我解:xy=1/z,x+y=2- 2020-10-31 …
1.(2X-1)(4x^2-1)(2X-1)2.(a-2b+3c)(a+2b-3c)3.(-a^2+ 2020-10-31 …
(1).-3ma^3+6ma^-12ma(2).x^6n+2+2x^3n+2+x^2(3).5(x- 2020-10-31 …
观察下列各式然后回答问题:1-1/2^2=1/2*2/3,1-1/3^2+2/3*4/3,1-1/4 2020-11-01 …
直接写出得数.0.5×4÷0.5×4=4.2-4.2×0.5=1.2÷4×1.2÷4=6.3+6.3 2020-11-19 …
已知a,b属于正实数a^2+b^2/2=1求y=a√(1+b^2)的最大值参考书上是用y^2=[a√ 2020-12-31 …
这些题怎么数学解1已知(x+m)^2(x^2-2x+3)+x(x+1)中不含x^2项求m的值2已知a 2020-12-31 …