早教吧作业答案频道 -->英语-->
1.,theresidentsranaway.A.ThecitytakenB.ThecityhavingbeentakenC.HavingtakenthecityD.Thecitybeingtaken2.TomsuggestedthattheyshouldgotoGreece,butMarysuggestedtoSpain.A.togoB.goingC.shouldgoD.went3.youcannotbe
题目详情
1.___,the residents ran away.
A.The city taken B.The city having been taken C.Having taken the city D.The city being taken
2.Tom suggested that they should go to Greece,but Mary suggested ___to Spain.
A.to go B.going C.should go D.went
3.you cannot be___careful when you drive a car.
A.very B.so C.too D.enough
4.Once environmental damage___,it takes many years for the system to recover.
A.has done B.is to do C.does D.is done
5.Word had come from the manager___a new transaction would be concluded.
A.who B.that C.which D.when
A.The city taken B.The city having been taken C.Having taken the city D.The city being taken
2.Tom suggested that they should go to Greece,but Mary suggested ___to Spain.
A.to go B.going C.should go D.went
3.you cannot be___careful when you drive a car.
A.very B.so C.too D.enough
4.Once environmental damage___,it takes many years for the system to recover.
A.has done B.is to do C.does D.is done
5.Word had come from the manager___a new transaction would be concluded.
A.who B.that C.which D.when
▼优质解答
答案和解析
1b 考点为独立主格结构,被动用及物动词的过去分词或相应时态形式
2b 考点suggest解释为建议时的用法,主要有3点,suggest sb to do sth ,suggest doing sth,suggest that 从句(should的虚拟语气,should可以省略)
3c cannot be too +形容词 解释,再怎么样也不过分,cannot be_too__careful 也就是越细心越好
4d 对于名词damage(破坏)只能是被形成,而不是(它自己)形成,所以要选被动,只有d是被动
5b
考点为同为从句用that引导,word的前不加表示数量的词时解释为news(消息),为不可数名词,word came that a new transaction(交易) would be concluded(被敲定).有个消息传来,说的是有项新交易将达成.
希望能帮到楼主
2b 考点suggest解释为建议时的用法,主要有3点,suggest sb to do sth ,suggest doing sth,suggest that 从句(should的虚拟语气,should可以省略)
3c cannot be too +形容词 解释,再怎么样也不过分,cannot be_too__careful 也就是越细心越好
4d 对于名词damage(破坏)只能是被形成,而不是(它自己)形成,所以要选被动,只有d是被动
5b
考点为同为从句用that引导,word的前不加表示数量的词时解释为news(消息),为不可数名词,word came that a new transaction(交易) would be concluded(被敲定).有个消息传来,说的是有项新交易将达成.
希望能帮到楼主
看了 1.,theresident...的网友还看了以下:
1.如果a≠0,p是正整数,那么下列各式中错误的是:()A.a^-p=1/a^pB.a^-p=(1/ 2020-03-30 …
求出下列各式中的字母a的取值范围:1.a<a/22.a<1/a3.|a|/a=-14.1/a>a>0 2020-03-30 …
1.a>0且a≠1①㏒a(1)+㏒a(a)②㏒a(a²)-aˆ㏒a(3)2.若6ˆa=8,求㏒6(4 2020-03-30 …
a=xa+a=a+x2a=a+x2a-2x=a+x-2x2(a-x)=a-x2=1到底a=xa+a= 2020-03-30 …
1.a≠0,b≠0,则a/|a|+b/|b|的不同取值的个数为()A.3B.2C.1D.02.若|x 2020-03-31 …
1.判断a、b、c能否构成三角形的三条边长的条件是().选项:a、a>0&&b>0&&c>0b、a+ 2020-03-31 …
设函数f(x)在x=a处二阶可导,又limf'(x)/(x-a)=-1,则()A.x=a是f(x设函 2020-03-31 …
(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a-1)[(a+1)(a^ 2020-05-22 …
1.,theresidentsranaway.A.ThecitytakenB.Thecityhav 2020-07-26 …
递回关系式的运算公式(数列)以下是推导一个公式"a=a+r(1-p^n)/(1-p)"的过程a=p* 2021-01-13 …