Thedistancesan.Thedistancesanobjectfallsfromrestintimetsecondsisgiveninfeetbys(t)=16t².Find(a)s(2)(b)s(3)(c)[s(3.01)-s(3)]/0.01

Question

The distance s an .
The distance s an object falls from rest in time t seconds is given in feet by s(t) = 16t².
Find
(a) s(2)
(b) s(3)
(c) [s(3.01) -s(3)]/0.01

Answer 1

s(t) = 16t²
(a) s(2)
=16*2^2=64
(b) s(3)
=16*3^2=144
(c) [s(3.01) -s(3)]/0.01
=16*(3.01^2-3^2)/0.01
=16*6.01*0.01/0.01
=16*6.01
=96.16