早教吧作业答案频道 -->数学-->
matlab-1/18*pi*(2*a+3-b)^2*(2*a-b-6)+1/18*pi*(-6*a+3-b)^2*(6*a+b+6)+(9*asin(-1/3*b-2*a)*b+54*asin(-1/3*b-2*a)*a-9*(9-12*b*a-36*a^2-b^2)^(1/2)+1/3*(9-12*b*a-36*a^2-b^2)^(3/2)+36*pi*a-9*asin(-1/3*b+2/3*a)*b+9*(9-b^2+4*b*a-4*a^2)^(1/2)-1/3*(9-b^2+4*b*a
题目详情
matlab
-1/18*pi*(2*a+3-b)^2*(2*a-b-6)+1/18*pi*(-6*a+3-b)^2*(6*a+b+6)+(9*asin(-1/3*b-2*a)*b+54*asin(-1/3*b-2*a)*a-9*(9-12*b*a-36*a^2-b^2)^(1/2)+1/3*(9-12*b*a-36*a^2-b^2)^(3/2)+36*pi*a-9*asin(-1/3*b+2/3*a)*b+9*(9-b^2+4*b*a-4*a^2)^(1/2)-1/3*(9-b^2+4*b*a-4*a^2)^(3/2)+18*asin(-1/3*b+2/3*a)*a)/a=-1014.1
-1/18*pi*(2*a+3-2*b)^2*(2*a-2*b-6)+1/18*pi*(-6*a+3-2*b)^2*(6*a+2*b+6)+(18*asin(-2/3*b-2*a)*b+54*asin(-2/3*b-2*a)*a-9*(9-24*b*a-36*a^2-4*b^2)^(1/2)+1/3*(9-24*b*a-36*a^2-4*b^2)^(3/2)+36*pi*a-18*asin(-2/3*b+2/3*a)*b+9*(9-4*b^2+8*b*a-4*a^2)^(1/2)-1/3*(9-4*b^2+8*b*a-4*a^2)^(3/2)+18*asin(-2/3*b+2/3*a)*a)/a=-1004.2
-1/18*pi*(2*a+3-b)^2*(2*a-b-6)+1/18*pi*(-6*a+3-b)^2*(6*a+b+6)+(9*asin(-1/3*b-2*a)*b+54*asin(-1/3*b-2*a)*a-9*(9-12*b*a-36*a^2-b^2)^(1/2)+1/3*(9-12*b*a-36*a^2-b^2)^(3/2)+36*pi*a-9*asin(-1/3*b+2/3*a)*b+9*(9-b^2+4*b*a-4*a^2)^(1/2)-1/3*(9-b^2+4*b*a-4*a^2)^(3/2)+18*asin(-1/3*b+2/3*a)*a)/a=-1014.1
-1/18*pi*(2*a+3-2*b)^2*(2*a-2*b-6)+1/18*pi*(-6*a+3-2*b)^2*(6*a+2*b+6)+(18*asin(-2/3*b-2*a)*b+54*asin(-2/3*b-2*a)*a-9*(9-24*b*a-36*a^2-4*b^2)^(1/2)+1/3*(9-24*b*a-36*a^2-4*b^2)^(3/2)+36*pi*a-18*asin(-2/3*b+2/3*a)*b+9*(9-4*b^2+8*b*a-4*a^2)^(1/2)-1/3*(9-4*b^2+8*b*a-4*a^2)^(3/2)+18*asin(-2/3*b+2/3*a)*a)/a=-1004.2
▼优质解答
答案和解析
您的问题很容易解决.
输入：
syms a b
[a,b]=solve('-1/18*pi*(2*a+3-b)^2*(2*a-b-6)+1/18*pi*(-6*a+3-b)^2*(6*a+b+6)+(9*asin(-1/3*b-2*a)*b+54*asin(-1/3*b-2*a)*a-9*(9-12*b*a-36*a^2-b^2)^(1/2)+1/3*(9-12*b*a-36*a^2-b^2)^(3/2)+36*pi*a-9*asin(-1/3*b+2/3*a)*b+9*(9-b^2+4*b*a-4*a^2)^(1/2)-1/3*(9-b^2+4*b*a-4*a^2)^(3/2)+18*asin(-1/3*b+2/3*a)*a)/a=-1014.1','-1/18*pi*(2*a+3-2*b)^2*(2*a-2*b-6)+1/18*pi*(-6*a+3-2*b)^2*(6*a+2*b+6)+(18*asin(-2/3*b-2*a)*b+54*asin(-2/3*b-2*a)*a-9*(9-24*b*a-36*a^2-4*b^2)^(1/2)+1/3*(9-24*b*a-36*a^2-4*b^2)^(3/2)+36*pi*a-18*asin(-2/3*b+2/3*a)*b+9*(9-4*b^2+8*b*a-4*a^2)^(1/2)-1/3*(9-4*b^2+8*b*a-4*a^2)^(3/2)+18*asin(-2/3*b+2/3*a)*a)/a=-1004.2')
即可
得到答案：
a =
2.2631583455459650748817198905258883*i + 1.6745743664836895630189592867119955
b =
- 0.64237911443082413277089195366176*i - 0.37353976784828553808533671310449
i表示-1的平方根.
输入：
syms a b
[a,b]=solve('-1/18*pi*(2*a+3-b)^2*(2*a-b-6)+1/18*pi*(-6*a+3-b)^2*(6*a+b+6)+(9*asin(-1/3*b-2*a)*b+54*asin(-1/3*b-2*a)*a-9*(9-12*b*a-36*a^2-b^2)^(1/2)+1/3*(9-12*b*a-36*a^2-b^2)^(3/2)+36*pi*a-9*asin(-1/3*b+2/3*a)*b+9*(9-b^2+4*b*a-4*a^2)^(1/2)-1/3*(9-b^2+4*b*a-4*a^2)^(3/2)+18*asin(-1/3*b+2/3*a)*a)/a=-1014.1','-1/18*pi*(2*a+3-2*b)^2*(2*a-2*b-6)+1/18*pi*(-6*a+3-2*b)^2*(6*a+2*b+6)+(18*asin(-2/3*b-2*a)*b+54*asin(-2/3*b-2*a)*a-9*(9-24*b*a-36*a^2-4*b^2)^(1/2)+1/3*(9-24*b*a-36*a^2-4*b^2)^(3/2)+36*pi*a-18*asin(-2/3*b+2/3*a)*b+9*(9-4*b^2+8*b*a-4*a^2)^(1/2)-1/3*(9-4*b^2+8*b*a-4*a^2)^(3/2)+18*asin(-2/3*b+2/3*a)*a)/a=-1004.2')
即可
得到答案：
a =
2.2631583455459650748817198905258883*i + 1.6745743664836895630189592867119955
b =
- 0.64237911443082413277089195366176*i - 0.37353976784828553808533671310449
i表示-1的平方根.
看了 matlab-1/18*pi...的网友还看了以下：
（4/3-5/3）÷10/7（3/2+9/2）÷21/201-14/5÷7/5（4/3-5/3）÷ 2020-05-17 …
帮我破解下这串数字什么意思9(2)4(3)6(2)2(1)4(3)3(1)4(3)9(1)6(3) 2020-05-17 …
求1+2+2^2+2^3+2^4+…+2^2014的值.设S=1+2+2^2+2^3+2^4+…+ 2020-07-09 …
计算题：4/7+1/2*8/72/13*12除6/135/6除(2/3-5/12)(5/6+2/3 2020-07-18 …
matlab-1/18*pi*(2*a+3-b)^2*(2*a-b-6)+1/18*pi*(-6* 2020-07-24 …
xyz=1,x+y+z=2,x^2+y^2+z^2=3,求x,y,z我解:xy=1/z,x+y=2- 2020-10-31 …
观察下列各式然后回答问题:1-1/2^2=1/2*2/3,1-1/3^2+2/3*4/3,1-1/4 2020-11-01 …
数列(1/4+9),(1/2+9/2),(3/4+3),(1+9/4),(5/4+9/5),…中,数 2020-11-06 …
已知a,b属于正实数a^2+b^2/2=1求y=a√(1+b^2)的最大值参考书上是用y^2=[a√ 2020-12-31 …
这些题怎么数学解1已知(x+m)^2(x^2-2x+3)+x(x+1)中不含x^2项求m的值2已知a 2020-12-31 …