早教吧作业答案频道 -->英语-->
mathematicsoffinance数学题求解1.1.Mrs.SinghowesMr.Valdy$55,513.78in14-months.Mr.Valdyagreestoletherrepaytheloanwithapaymentof$35,000in6-months,$10,000in8-monthsand$Xin14-months.Ifmoneyisworthj4=6%,whatistheval
题目详情
mathematics of finance数学题求解
1.1.Mrs.Singh owes Mr.Valdy $55,513.78 in 14-months.Mr.Valdy agrees to let her repay the loan with a payment of $35,000 in 6-months,$10,000 in 8-months and $X in 14-months.If money is worth j4 = 6%,what is the value of X,using 14-months as the focal date along with the exact method of crediting/charging interest?
2.2.A car insurance company charges you a premium of $1452 a year for your car insurance policy.You have two options.Option 1 is to pay the $1452 in cash today.Option 2 is to make three payments of $499 at the following times:today,3-months from now and 6-months from now.What nominal rate of interest,j4,are you being charged?
1.1.Mrs.Singh owes Mr.Valdy $55,513.78 in 14-months.Mr.Valdy agrees to let her repay the loan with a payment of $35,000 in 6-months,$10,000 in 8-months and $X in 14-months.If money is worth j4 = 6%,what is the value of X,using 14-months as the focal date along with the exact method of crediting/charging interest?
2.2.A car insurance company charges you a premium of $1452 a year for your car insurance policy.You have two options.Option 1 is to pay the $1452 in cash today.Option 2 is to make three payments of $499 at the following times:today,3-months from now and 6-months from now.What nominal rate of interest,j4,are you being charged?
▼优质解答
答案和解析
1.1 X={[(55513.78*(1+j)^6-35000]*(1+J)^2-10000}*(1+J)^6=12800.08 (j=0.5%)
1.2 according the question factor establish the equation 1452*(1+j)^6=499*[(1+j)^6+(1+j)^3+1],
replace (1+j)^3 with r,therefore:(1452-499)*r^2-499*r-499=0,
the solution for above equation is r=1.031318583,
hence j=r^(1/3)-1=1.0103324-1=0.010,
thus we can get nominal rate of interest j4=12*j=0.12≈12%.
1.2 according the question factor establish the equation 1452*(1+j)^6=499*[(1+j)^6+(1+j)^3+1],
replace (1+j)^3 with r,therefore:(1452-499)*r^2-499*r-499=0,
the solution for above equation is r=1.031318583,
hence j=r^(1/3)-1=1.0103324-1=0.010,
thus we can get nominal rate of interest j4=12*j=0.12≈12%.
看了 mathematicsoff...的网友还看了以下:
已知字母组合成英语单词1、e e t t i n h r 2、e e r a t w h 3、o 2020-05-14 …
一质点沿直线OX方向做加速运动,它离开O点的距离X随时间T的变化关系为X=5+〔2(T的3次方)〕 2020-05-20 …
The customer asks your project to be completed 6 m 2020-05-26 …
甲乙两地生产某种商品,他们可调出数量分别为300t和750t,a,b,c三地需要该产品的数量分别为 2020-07-09 …
这是题中的例子“把i=5∠53.1°用正弦电流的瞬时表达式表示为:i=5√2sin(100πt+5 2020-07-17 …
复数(t²+t-2)-(t²+5t-6)i(t∈R),当t等于几时是纯虚数?y=6^x-2的反函数 2020-07-30 …
复数(t2+t-2)-(t2+5t-6)i(t∈R),当t等于几时是纯虚数?y=6^x-2的反函数 2020-07-30 …
帮忙求个递推公式,从兔子繁殖问题衍生而来.m(0)=1,m(1)=1,m(2)=1,m(3)=2, 2020-08-01 …
一题大学物化题某电池的电动势与温度的关系式为;E=0.0694+1.881×10-3T/K2.9× 2020-11-05 …
工厂有一容量为300吨的水塔,每天从早6时起到晚10时止供应该厂的生产和生活用水该厂生活用水为每小时 2020-11-08 …