早教吧作业答案频道 -->英语-->
Alistofnumbershasameanof8andastandarddeviationof2.5.Ifxisanumberinthelistthatis2standarddeviationsabovethemean,whatisthevalueofx答案x=8+2.5*2=13
题目详情
A list of numbers has a mean of 8 and a standard deviation of 2.5.If x is a number in the list that is 2 standard deviations above the mean,what is the value of x
答案x=_8+2.5*2=13
答案x=_8+2.5*2=13
▼优质解答
答案和解析
一组数据的均值为8,标准差为2.5,如果x超过均值2倍的标准差,则x是多少?
x=8+2×2.5=13
x=8+2×2.5=13
看了 Alistofnumbers...的网友还看了以下:
u^2/(u^2+3u+2)=1+1/(u+1)-4/(u+2)等号左边是用什么方法变成等号右边的 2020-05-13 …
设f(x+1/x)=x2+1/x2,求f(x)设u=x+1/x,求f(u)=(u^2±√u^2-4 2020-06-12 …
求1+2+2^2+2^3+2^4+…+2^2014的值.设S=1+2+2^2+2^3+2^4+…+ 2020-07-09 …
用matlab画一个函数的三维图像。sqrt(u^2+v^2)d0时,h=0,画出h与u、v的三维 2020-07-09 …
函数w=1/z,把z平面上x^2+(y-1)^2=4映射成w平面上怎样的曲线?z=1/w=1/(u 2020-07-30 …
分式方程(u-2v)/(u+2v)-2/u^2-4v^2答案是(u-2v)^2+2/u^2-4v^ 2020-08-01 …
xyz=1,x+y+z=2,x^2+y^2+z^2=3,求x,y,z我解:xy=1/z,x+y=2- 2020-10-31 …
观察下列各式然后回答问题:1-1/2^2=1/2*2/3,1-1/3^2+2/3*4/3,1-1/4 2020-11-01 …
已知a,b属于正实数a^2+b^2/2=1求y=a√(1+b^2)的最大值参考书上是用y^2=[a√ 2020-12-31 …
这些题怎么数学解1已知(x+m)^2(x^2-2x+3)+x(x+1)中不含x^2项求m的值2已知a 2020-12-31 …