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高一对数运算,1、(lg根27+lg8-lg根1000)/(lg1.2)2、(1/2)lg(32/49)-(4/3)lg根8+lg根245
题目详情
高一对数运算,
1、(lg根27+lg8-lg根1000)/(lg1.2)
2、(1/2)lg(32/49)-(4/3)lg根8+lg根245
1、(lg根27+lg8-lg根1000)/(lg1.2)
2、(1/2)lg(32/49)-(4/3)lg根8+lg根245
▼优质解答
答案和解析
1、(lg根27+lg8-lg根1000)/(lg1.2)
=[lg3^(3/2)+lg2^3-lg10^(3/2)]/(lg1.2)
=[lg3^(3/2)+lg4^(3/2)-lg10^(3/2)]/(lg1.2)
=(3/2)(lg3+lg4-lg10)/(lg1.2)
=(3/2)lg(3*4/10)/lg1.2
=(3/2)lg1.2/lg1.2
=3/2
2、(1/2)lg(32/49)-(4/3)lg根8+lg根245
=(1/2)lg(2^5/7^2)-(4/3)lg2^(3/2)+lg(5*7^2)^(1/2)
=(1/2)lg(2^5/7^2)-(4/3)*(3/2)lg2+(1/2)*lg(5*7^2)
=(1/2)[lg(2^5/7^2)+lg(5*7^2)]-2lg2
=(1/2)lg(2^5*5)-2lg2
=(1/2)lg(2^4*10)-2lg2
=(1/2)lg2^4+(1/2)*lg10-2lg2
=2lg2+1/2-2lg2
=1/2
=[lg3^(3/2)+lg2^3-lg10^(3/2)]/(lg1.2)
=[lg3^(3/2)+lg4^(3/2)-lg10^(3/2)]/(lg1.2)
=(3/2)(lg3+lg4-lg10)/(lg1.2)
=(3/2)lg(3*4/10)/lg1.2
=(3/2)lg1.2/lg1.2
=3/2
2、(1/2)lg(32/49)-(4/3)lg根8+lg根245
=(1/2)lg(2^5/7^2)-(4/3)lg2^(3/2)+lg(5*7^2)^(1/2)
=(1/2)lg(2^5/7^2)-(4/3)*(3/2)lg2+(1/2)*lg(5*7^2)
=(1/2)[lg(2^5/7^2)+lg(5*7^2)]-2lg2
=(1/2)lg(2^5*5)-2lg2
=(1/2)lg(2^4*10)-2lg2
=(1/2)lg2^4+(1/2)*lg10-2lg2
=2lg2+1/2-2lg2
=1/2
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