()19.(2015•广东)一SirJennywantstoknowwhenshecanleavetheoffice.—Onlywhenshecopyingthisreport.A.finishesB.finishC.finishedD.willfinish
() 19. (2015 •广东) 一Sir Jenny wants to know when she can leave the office.
—Only when she copying this report.
A. finishes B. finish
C. finished D. will finish
() 19. (2015 •广东) 一Sir Jenny wants to know when she can leave the office.
—Only when she copying this report.
A. finishes B. finish
C. finished D. will finish
() 19. (2015 •广东) 一Sir Jenny wants to know when she can leave the office.
) 19. (2015 •广东) 一Sir Jenny wants to know when she can leave the office.—Only when she copying this report.
copying this report.A. finishes B. finish
C. finished D. will finish
如果n=1,f(n)=1;n=2,f(n)=3;n=3,f(n)=6;n=4,f(n)=10;那么当 2020-03-30 …
1.求数列1,x+x^2,x^2+x^3+x^4,x^3+x^4+x^5+x^6,...前n项之和2 2020-03-30 …
这是什么迭代公式?x(n+1)=x(n)-2*f(x(n))*f1(x(n))/(2*f1(x(n 2020-04-27 …
哥德巴猜想 ,素数,函数 500分求一个 函数 f(x) 使得 对于 任何一个大于6的正整数 n 2020-05-14 …
已知数列{(N):F(1)=1,F(2)=1,当N>2时,F(N)=3,F(N-2)–F(N-1) 2020-05-16 …
任意x∈R,函数f(x)满足f(x+1)=/{f(x)-[f(x)]2}+1/2,设an=[f(n 2020-06-12 …
14.对任意x属于R,函数f(x)满足f(x+1)={√f(x)-[f(x)]^2}+1/2,设a 2020-06-24 …
已知f(0)=f(1)=1f(2)=0f(n)=f(n-1)-2f(n-2)+f(n-3)(n>2 2020-07-13 …
斐波那契数列解法中的一个问题求解?这是解法裴波那契数列:1,1,2,3,5,8,13,.裴波那契数 2020-07-23 …
设f(0)=0,f(x)的二阶导数在x=0的某邻域连续,求U=f(1/n^2)+f(2/n^2)+ 2020-07-31 …